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3 years ago

The circumference for a circle that has a radius or 7 inches is

Mathematics

1 answer:

lidiya [134]3 years ago

7 0

Circumference
C=2πr
C=2(3.14)(7)
C=(3.14)(14)
C=43.96

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A triangle has two sides of lengths 7 and 12. What value could the length of

Alex73 [517]

Answer:

The length of the third side is 23

Step-by-step explanation:

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3 years ago

Find the measurement of an interior angle of a regular decagon (10-sided figure).

natita [175]

Answer:

144°

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Geometry

Sum of Angles: 180(n - 2)

Step-by-step explanation:

Step 1: Define

Number of sides n = 10

Step 2: Find

Substitute: 180(10 - 2)
Subtract: 180(8)
Multiply: 1440°

Step 3: Find 1 angle

We have 10 sides.

Divide: 1440/10 = 144

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3 years ago

ArbitrLikvidat [17]

Answer:

18 girls

Step-by-step explanation:

6:9

6+9 = 15

we multiply each part of the ratio by 3

6*3 = 18 girls

9*3 = 27 boys

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3 years ago

Will give brainliest

Ostrovityanka [42]

$\displaystyle\\\sum_{n=1}^7(4n+2)$

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4 years ago

Write the matrix equation as a system of linear equations without matrices. [Start 3 By 3 Matrix 1st Row 1st Column 1 2nd Column

ASHA 777 [7]

Answer:

$x-2y-4z=8\\5x-4y+7z=5\\-7x+5y+2z=-3$

Step-by-step explanation:

Given the matrix equation below:

$\left(\begin{array}{ccc}1&-2&-4\\5&-4&7\\-7&5&2\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}8\\5\\-3\end{array}\right)$

We are required to write the matrix equation as a system of linear equations without matrices.

$\left(\begin{array}{ccc}1&-2&-4\\&&\\&&\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}8\\&\\&\end{array}\right)$is equivalent to: x-2y-4z=8$

$\left(\begin{array}{ccc}\\5&-4&7\\&&\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}&\\5\\&\end{array}\right)$ is equivalent to: 5x-4y+7z=5$

$\left(\begin{array}{ccc}&\\&\\-7&5&2\end{array}\right)\left(\begin{array}{ccc}x\\y\\z\end{array}\right) =\left(\begin{array}{ccc}&\\&\\-3\end{array}\right)$ is equivalent to: -7x+5y+2z=-3$

Therefore, we have the system of equations:

$x-2y-4z=8\\5x-4y+7z=5\\-7x+5y+2z=-3$

8 0

3 years ago