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ElenaW [278]
3 years ago
7

Which of the following statements best describes the relationship of a relation in the functions like on the play

Mathematics
1 answer:
dolphi86 [110]3 years ago
4 0

Answer:

- A function is always a relation.

- A relation is a function, if and only if, the x- values do not repeat in a given set.

Step-by-step explanation:

I hope this helps UvU

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lys-0071 [83]
5/8 or .625 is the answer                
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It took Lisa 2 hours to read the first 100 pages of a book. Then she read the last 44 pages in 1 hour. How many pages did she re
ra1l [238]
The book has 100+44=144 pages.
She spent 2+1=3 hours on reading = 3*60=180 minutes
The "speed" will be 144/180 = 0.8 pages per minute
8 0
3 years ago
What is (-7624928) * 997 + 7624928 * (-3)
DiKsa [7]

Answer:

<u><em>-7624928000 </em></u><em>is the right answer.</em>

Step-by-step explanation:

<em> (-7624928) × 997 + 7624928 × (-3)</em>

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= <u><em>-7624928000</em></u><em>        </em><u><em>Ans..</em></u>

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5 0
2 years ago
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Historically, there is a 40% chance of having clear sunny skies in Seattle in July. Let's assume that each day is independent fr
Igoryamba

Answer: a)  0.0058

b) 0.0026

Step-by-step explanation:

Given : The probability of having clear sunny skies in Seattle in July : p= 0.40

The number of days spent in Seattle  in July: n= 18

a) Using, Binomial probability formula : P(x)=^nC_xp^x(1-p)^{n-x}

The probability of having clear sunny skies on at least 13 of those days:-

P(x\geq13)=P(13)+P(14)+P(15)+P(16)+P(17)+P(18)\\\\=^{18}C_{13}(0.4)^{13}(0.6)^5+^{18}C_{14}(0.4)^{14}(0.6)^4+^{18}C_{15}(0.4)^{15}(0.6)^3+^{18}C_{16}(0.4)^{16}(0.6)^2+^{18}C_{17}(0.4)^{17}(0.6)^1+^{18}C_{18}(0.4)^{18}(0.6)^0

=\dfrac{18!}{13!5!}(0.4)^{13}(0.6)^5+\dfrac{18!}{14!4!}(0.4)^{14}(0.6)^4+\dfrac{18!}{15!3!}(0.4)^{15}(0.6)^3+\dfrac{18!}{16!2!}(0.4)^{16}(0.6)^2+(18)(0.4)^{17}(0.6)^1+(1)(0.4)^{18}

=0.00447111249474+0.00106455059399+0.000189253438931+0.0000236566798664+0.00000185542587187+0.000000068719476736

=0.00575049735288\approx0.0058

b) On converting binomial to normal distribution, we have

\text{Mean=}\mu=np= 18\times0.40=7.2\\\\\text{Standard deviation}=\sigma=\sqrt{np(1-p)}\\\\=\sqrt{18(0.40)(1-0.40)}=2.07846096908\approx2.08

Let x be the number of days having clear sunny skies in Seattle in July.

Then, using z=\dfrac{x-\mu}{\sigma} we have

z=\dfrac{13-7.2}{2.08}=2.78846153846\approx2.79

P-value = P(x\geq13)=P(z\geq2.79)=1-P(z

=1-0.9973645=0.0026355\approx0.0026

6 0
3 years ago
2x-y=-11 Y=-2x-13<br> Solve by using elimination
Crazy boy [7]

Answer:

x = -6 ; y = -1

Step-by-step explanation:

2 x - y = - 11   .........equ No 1

- 2 x - y =  13 .........equ No 2

Adding equ  No. 1 and equ No. 2

- 2 y  = 2

∴ y = - 1

substituting y = -1 in equ no 1

2 x - ( -1) = -11

2 x + 1 = - 11

2 x = -11 - 1

2 x = -12

∴ x = -6

x = -6 ; y = -1

8 0
3 years ago
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