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spin [16.1K]
3 years ago
15

For every four female students in a training class, there are two men. What is the ratio of female to male students ?

Mathematics
2 answers:
vfiekz [6]3 years ago
7 0
4/2. four women to two men

xxTIMURxx [149]3 years ago
3 0
2:1 female to male students hope this helps
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For a field trip, the school bought 47 sandwiches for $4.60 each and 39 bags of chips for $1.25 each. How much did the school sp
NNADVOKAT [17]

Answer:  \$264.95

Step-by-step explanation:

You know that 1 sandwich costs $4.60 and the school bought 47 sandwiches.

Therefore, in order to calculate the total cost of 47 sandwiches, you need  to multiply this number of sandwiches bought by the schoole, by the cost of 1 sandwich. Then:

sandwiches=(47)(\$4.60)\\\\sandwiches=\$216.2

You know that 1 bag of chip costs $1.25 and the school bought  39 bags of chips.

So, in order to calculate the total cost of  39 bags of chips, you must  multiply the total number of them bought by the school, by the cost of 1 bag of chips.

Then:

bag\ of\ chips=(39)(\$1.25)\\\\bag\ of\ chips=\$48.75

Therefore, the total amount school spent was:

Total\ spent=\$216.2+\$48.75\\\\Total\ spent=\$264.95

8 0
3 years ago
Read 2 more answers
Evaluate the following expression. 3^-2
OverLord2011 [107]
3^-2 = 0.111111111 ← Answer
7 0
3 years ago
Solve <br> 6r + 7 = 13 + 7r
Firdavs [7]

Answer:

r = -6

Step-by-step explanation:

6r + 7 = 13 + 7r

-6r both sides

7 = 13 + r

-7 both sides

r + 6 = 0

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r = -6

8 0
3 years ago
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The product shown is a difference of squares. What is the missing constant term in the second factor?
34kurt
Difference of two squares is of the form (a + b)(a - b) or vice-versa. Here, a = -5x and b = 3.
(-5x - 3)(-5x + 3)
Answer: 3
7 0
3 years ago
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F(x)=(x+4)(x-2)(x+4)(x+4)<br><br> What is the multiple zero? Multiplicity is?
kari74 [83]
f(x)=(x+4)(x-2)(x+4)(x+4)\\f(x)=(x+4)^3(x-2)=0\\(x+4)^3=0~|~(x-2)=0\\(x+4)(x+4)(x+4)=0~|~x=2\\x=-4,2

The multiple zero is x = -4.

The multiplicity is 2 because there are two values of x.
8 0
2 years ago
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