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posledela
3 years ago
13

What are the values of x and y in the matrix equation below? (PICTURED)

Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0

Answer:

4.) x=-3 and y=4

Step-by-step explanation:

[x+4] + [-9x] = [28]

First plug in x into the equation

[-3+4] + [-9(-3)] = [28]

[1] + [27] = [28]

1+27=28 (True)

Next, plug in y into the equation

[y^2+1] + [-17] = [0]

[(4)(4)+1] + [-17] = [0]

[16+1] + [-17] = [0]

[17] + [-17] =[0]

17 + -17=0 (True)

The Answer is D- X = -3 and Y= 4

Masja [62]3 years ago
5 0

Given the matrix equation:

\left[\begin{array}{ccc}x+4\\y^{2}+1\end{array}\right]+\left[\begin{array}{ccc}-9x\\-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]

i.e., \left[\begin{array}{ccc}x+4-9x\\y^{2}+1-17\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]

i.e., \left[\begin{array}{ccc}4-8x\\y^{2}-16\end{array}\right]=\left[\begin{array}{ccc}28\\0\end{array}\right]

Now, comparing left hand side with right side, we have:

4-8x = 28                      and                 y^{2}-16=0

i.e., -8x = 28-4              and                 y^{2}=16

i.e., -8x=24                    and                y=\pm\sqrt{16}

i.e., x=\frac{24}{-8}        and                 y=\pm4

i.e., x = -3                      and                 y=+4,-4

Hence, third option is correct.

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