Answer:
Cosec <F = 73/55
Step-by-step explanation:
In ΔEFG, the measure of ∠G=90°, GF = 48, EG = 55, and FE = 73. What ratio represents the cosecant of ∠F?
First you must know that;
Cosecant <F = 1/sin<F
Given
∠G=90°, GF = 48, EG = 55, and FE = 73.
ED ,= hyp = 73
EG = opp = 55*side facing <F
Using DOH CAH TOA
Sin theta = opp/hyp
Sin <F= 55/73
Reciprocate both sides
1/sinF = 73/55
Cosec <F = 73/55
Answer:
yes
Step-by-step explanation:
if my eyes are good then yes
There are certain rules to follow when rotating a point 90 deg clockwise. Since it is given that ABCD is a parallelogram and the coordinates of point C are given, we just have to follow this simple relation:
R(90 deg) : (X,Y) ---> (-Y,X)
Using the given coordinates:
R(90 deg<span>) : (-4,1) ---> (-1,-4)
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Therefore, Point C' will be located at (-1,-4)
I can't understand what you wanted with the second question (or if that is even a question), but the answer to the first one is 42.