Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
4/3 because (check the picture)
Answer:
It would be 112.654 kilometers
Step-by-step explanation:
Answer:
(x+9)(3x+27)
Step-by-step explanation:
3x^2+54x+243 (243×3=729, Product=729, Sum=54) [27+27=54, 27×27=729]
3x^2+27x+27x+243
3x(x+9)+27(x+9)
=(x+9)(3x+27)
Answer:
49
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