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LekaFEV [45]
3 years ago
7

Yo can someone help me out

Mathematics
2 answers:
Sidana [21]3 years ago
7 0

Answer:

A

Step-by-step explanation:

nika2105 [10]3 years ago
3 0

Answer:

A

Step-by-step explanation:

The answer is A

p <18

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9<br> Find the values of r and y.<br> с<br> A<br> 95°<br> B<br> 4x<br> ro<br> D<br> E
Inga [223]

Answer:

  • x = 18°, y = 167°

Step-by-step explanation:

<u>In right triangle sum of two angles is 90°</u>

  • 4x + x = 90°
  • 5x = 90°
  • x = 90°/5
  • x = 18°

<u>Angle y is exterior angle and equals non-adjacent interior angles</u>

  • y = 4x + 95° =
  • 4*18° + 95° =
  • 72° + 95° =
  • 167°
4 0
2 years ago
X - 2y = -3<br> 2x + y = -1
bezimeni [28]

Answer:

y = 1

x = -1

Step-by-step explanation:

x - 2y = -3, then x = 2y - 3

2x + y = -1

substitute for x:

2(2y - 3) + y = -1

4y - 6 + y = -1

5y = 5

y = 1

x = 2 - 3 = -1

3 0
2 years ago
Read 2 more answers
-5+|-15÷(-5) |2(-5) ​
pav-90 [236]

Answer:

The value of this expression is -35.

Step-by-step explanation:

Let's use the order of operations (PEMDAS), to solve this problem.

-5+|-15/-5|*2*(-5)\\-5+3*-10\\-5+-30\\-35

In conclusion, the value of this expression is -35. Hope this helped :D

7 0
3 years ago
nathan smiled at 50 people one day and recorded that 36 people smiled back at him.Based on his observations how many people shou
Olegator [25]

Given :

Nathan smiled at 50 people one day and recorded that 36 people smiled back at him.

To Find :

How many people should Nathan expect to return a smile if he smiles at 650 people over a period of time.

Solution :

Ratio of people smiled by total number of people is :

R = \dfrac{36}{50}

Now, it is given that we have to use the given conditions.

Therefore, ratio will be same :

\dfrac{s}{650}=\dfrac{36}{50}\\\\s = \dfrac{36}{50}\times 650\\\\s = 468

Therefore, number of smiles Nathan expect to return is 468.

4 0
3 years ago
Please help me I will give you a Brainly
d1i1m1o1n [39]

Answer:

I would be y

Step-by-step explanation:

sorry if it is wrong

3 0
2 years ago
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