Random numbers for a simulation might come from
1) a table of random numbers
2) a computer random number generator, such as ones available in many spreadsheet programs
3) digitizing the noise of the Universe. Such random numbers are available on some web sites.
Very confident because a correlation coefficient of 1 is perfect then a correlation coefficient of .96 means it is like 96% accurate
The formula is Opposite/Hypotenuse
Answer:
length : 8 m
width : 13/2 = 6.5 m
Step-by-step explanation:
area of rectangle = l(ength)×w(idth) = 52
l = 2w - 5
=> (2w - 5)×w = 52
=> 2w² -5w - 52 = 0
we know, when transforming this quadratic equation into a multiplication of two expressions of w, that we need to have 2w and w (to make 2w²), and then which 2 numbers multiply to 52 and add to -5 (when one is multiplied by 2 due to 2w) : -13 and 4
=> (2w - 13)×(w + 4) = 0
=> 2 solutions for w :
2w-13 = 0
2w = 13, w = 13/2
w+4 = 0, w = -4
negative values for a side length of a shape do not make sense, so the only usable solution is w = 13/2
=> l = 2w - 5 = 13 - 5 = 8
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out during work were 244 and those that never felt stressed out were 495.
Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B)
P(B) is the probability of having a male.
P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
= 244/739
= 0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
