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Korolek [52]
3 years ago
9

ill decides to move her fish from a 20 gallon aquarium to a 50 gallon aquarium. She added 3 tablespoons of salt to her old aquar

ium. If she wishes to maintain to same salinity level, how many tablespoons should she add to her new aquarium?
Mathematics
1 answer:
klemol [59]3 years ago
3 0

In the old aquarium, 3 tablespoons of salt were used for 20 gallons. That's a conversion ratio of

\dfrac{3\,\rm tbsp}{20\,\rm{gal}}=0.15\,\dfrac{\rm tbsp}{\rm gal}

That is, for every gallon of water in the aquarium, there was 0.15 tbsp of salt. So a 50 gallon aquarium, Ill should add

(50\,\rm{gal})\left(0.15\,\dfrac{\rm tbsp}{\rm gal}\right)=7.5\,\rm{tbsp}

to maintain the salinity.

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PLEASE HELP ITS DUE TODAY!!!
Flura [38]

6/8 = p/12= tan∅

so p= 9

brainliest

4 0
3 years ago
Read 2 more answers
Find the solution of 2/3x+1/4=-4/3
wolverine [178]
These questions can be daunting at first, but they're pretty simple to solve.

First, we need to establish a common denominator.  We have 2 / 3, 1 / 4, and
-4 / 3.  The least common denominator we can get is by multiplying 4 and 3 together to get 12.  So we will change the denominator as follows;

2 / 3, 1 / 4, -4 / 3  =  8 / 12, 3 / 12, -16 / 12

Now we can put these back into the equation.

8/12x + 3/12 = -16/12
8x + 3 = -16

It's simple math from here on out, but I'll show the process.  What we can basically do now is take away the denominator because it doesn't matter now that it's common.

Subtract 3 from both sides.  Now we have 8x = -19

Dividing by 8 on both sides of the equation will get you your answer.

x = -19/8


Hope this helps!
6 0
3 years ago
NO LINKS!!
tester [92]

Answer:

Step-by-step explanation:

6 0
2 years ago
This year the fifth grade collected 216 fewer plastic containers than the fourth grade.How many plastic containers did the fifth
kap26 [50]

Let number of plastic containers collected by fourth grade= x

Then number of plastic containers collected by fifth grade students=x-216

OR

If number of plastic container collected by fifth grade is y

then number of plastic container collected by fourth grade=y+216

So, we can write it as follows

⇒ number of plastic containers collected by fourth grade= number of plastic containers collected by fifth grade +216



7 0
3 years ago
where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤
marusya05 [52]

THIS IS THE COMPLETE QUESTION BELOW

The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.

Answer

$168.27

Step by step Explanation

Given p=90000/400+3x

With the limits of 40 to 50

Then we need the integral in the form below to find the average price

1/(g-d)∫ⁿₐf(x)dx

Where n= 40 and a= 50, then if we substitute p and the limits then we integrate

1/(50-40)∫⁵⁰₄₀(90000/400+3x)

1/10∫⁵⁰₄₀(90000/400+3x)

If we perform some factorization we have

90000/(10)(3)∫3dx/(400+3x)

3000[ln400+3x]₄₀⁵⁰

Then let substitute the upper and lower limits we have

3000[ln400+3(50)]-ln[400+3(40]

30000[ln550-ln520]

3000[6.3099×6.254]

3000[0.056]

=168.27

the average price p on the interval 40 ≤ x ≤ 50 is

=$168.27

8 0
3 years ago
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