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Korolek [52]
3 years ago
9

ill decides to move her fish from a 20 gallon aquarium to a 50 gallon aquarium. She added 3 tablespoons of salt to her old aquar

ium. If she wishes to maintain to same salinity level, how many tablespoons should she add to her new aquarium?
Mathematics
1 answer:
klemol [59]3 years ago
3 0

In the old aquarium, 3 tablespoons of salt were used for 20 gallons. That's a conversion ratio of

\dfrac{3\,\rm tbsp}{20\,\rm{gal}}=0.15\,\dfrac{\rm tbsp}{\rm gal}

That is, for every gallon of water in the aquarium, there was 0.15 tbsp of salt. So a 50 gallon aquarium, Ill should add

(50\,\rm{gal})\left(0.15\,\dfrac{\rm tbsp}{\rm gal}\right)=7.5\,\rm{tbsp}

to maintain the salinity.

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Which represents the polynomial below written in standard form?
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B. 4x^3}+\frac{x^2}{2}-3x+6

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A sphere and a cylinder have the same radius and height. The volume of the cylinder is 21m. what is the volume of the sphere.​
Goshia [24]

Answer:

The volume of the sphere is 14m³

Step-by-step explanation:

Given

Volume of the cylinder = 21m^3

Required

Volume of the sphere

Given that the volume of the cylinder is 21, the first step is to solve for the radius of the cylinder;

<em>Using the volume formula of a cylinder</em>

The formula goes thus

V = \pi r^2h

Substitute 21 for V; this gives

21 = \pi r^2h

Divide both sides by h

\frac{21}{h} = \frac{\pi r^2h}{h}

\frac{21}{h} = \pi r^2

The next step is to solve for the volume of the sphere using the following formula;

V = \frac{4}{3}\pi r^3

Divide both sides by r

\frac{V}{r} = \frac{4}{3r}\pi r^3

Expand Expression

\frac{V}{r} = \frac{4}{3}\pi r^2

Substitute \frac{21}{h} = \pi r^2

\frac{V}{r} = \frac{4}{3} * \frac{21}{h}

\frac{V}{r} = \frac{84}{3h}

\frac{V}{r} = \frac{28}{h}

Multiply both sided by r

r * \frac{V}{r} = \frac{28}{h} * r

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V = 14

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