Step-by-step explanation:
the surface area consists of 6 individual areas :
front and back (both are equal)
left and right (both are equal)
top and bottom
front and back are trapezoids.
the area of a trapezoid is
(base 1 + base 2)/2 × h
the bases are the 2 parallel sides.
in our case the area of one trapezoid is
(5 + 19)/2 × 12.1 = 145.2 ft²
front and back together then are 290.4 ft².
left and right are 8×14 rectangles:
8×14 = 112 ft²
together they are 224 ft².
the bottom is a 5×8 rectangle :
5×8 = 40 ft²
the top is a 19×8 rectangle :
19×8 = 152 ft²
so, the total surface area is
290.4 + 224 + 40 + 152 = 706.4 ft²
The area of the sector in the circle can be calculated using the formula:
A = <span>π r</span>² θ / 360
where r is the radius and θ is the area subtended by sector. So,
A = π (10)² (37/360)
The answer is the first option.
Answer:
1
Step-by-step explanation:
i am not sure if it is wrong i am sooo sorry
15 times 10 + 20 times 20 = 550
Basically, you are asking how many ways can 5 objects be chosen from 12 (the order is NOT important).
The formula for this is n! / [ r! * (n-r)! ]
12! / [5! * 7!] =
12*11*10*9*8*7! / (5! * 7!) =
12*11*10*9*8 / 5 * 4 * 3 * 2 =
11*9*8 =
792 different collections
Source:
http://www.1728.org/combinat.htm
