Answer:
c
Step-by-step explanation:
it just is
-sqrt(3) -i = 2 cis (7pi/6)
-sqrt(3) -i
We can find the radius
r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)
= sqrt( 3 + 1)
= sqrt(4)
= 2
theta = arctan (y/x)
arctan (-1/-sqrt(3))
arctan (1/sqrt(3))
theta = pi/6
But this is in the first quadrant, and we need it in the third quadrant
Add pi to move it to the third quadrant
theta = pi/6 + 6pi/6
=7pi/6
2/3 is larger
3/5 x 3/3 = 9/15
2/3 x 5/5 = 10/15
Answer: 8x+2
explanation:
i just solved it
It is Odd
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