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2 years ago

Convert -√3-i to polar form.

Mathematics

2 answers:

storchak [24]2 years ago

7 0

Answer:

Step-by-step explanation:

it just is

Jlenok [28]2 years ago

6 0

Answer:

-sqrt(3) -i = 2 cis (7pi/6)

Step-by-step explanation:

-sqrt(3) -i

We can find the radius

r = sqrt( (-sqrt(3)) ^2 + (-1) ^2)

= sqrt( 3 + 1)

= sqrt(4)

= 2

theta = arctan (y/x)

arctan (-1/-sqrt(3))

arctan (1/sqrt(3))

theta = pi/6

But this is in the first quadrant, and we need it in the third quadrant

Add pi to move it to the third quadrant

theta = pi/6 + 6pi/6

=7pi/6

-sqrt(3) -i = 2 cis (7pi/6)

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