Question

Identify an equation in point slope form for the line perpendicular to y=- 1/2x+11 that passes through (4,-8)

Answer 1

Required equation in point slope form is: y = 2x -16

Step-by-step explanation:

We need to find an equation  in point slope form for the line perpendicular to y= -1/2x+11 that passes through (4,-8)

The equation of point slope form is:

$y = mx+b$

where m is slope and b is the y-intercept

Finding Slope of required equation:

We can find slope by comparing this equation y= -1/2x+11 with standard y = mx+b equation.

m = -1/2

Since the lines are perpendicular the slope of line will be: -1/m

So, Slope of required equation is 2

Now finding b (y-intercept)

Putting y=-8, x=4 and m=2

y = mx + b

-8 = 2(4) + b

-8 = 8 + b

=> b = -8-8

b = -16

So, required equation having slope m=2 and y-intercept b = -16

y = mx + b

y = 2x -16

So, Required equation in point slope form is: y = 2x -16

Learn More about point slope form at:

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Keywords: point slope form, perpendicular line

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