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Ira Lisetskai [31]
3 years ago
7

Circle all the ODD NUMBERS UNDERLINE all the EVEN numbers

Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

You need to add a image

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Divide -1.53 ÷ 0.17 enter your answer in the box PLEASE HELLPPP
marshall27 [118]

Answer:

-9

Step-by-step explanation:

-1.53  ÷  0.17 =‬ -9

check work:

-9 x 0.17 = -1.53

6 0
3 years ago
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Find the product. -3x^ 3(-2x^ 2 + 4x + 7)
larisa86 [58]

Answer:

w

Step-by-step explanation:

w is the answer to all ur problems

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PLEASE HELP REALLY APRICATE IT
zaharov [31]
It should be 92 sorry if its wrong
7 0
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What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?<br><br> fast please
xxTIMURxx [149]

Answer:      6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.

step by step explanation:

\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}

Solution-

The quadratic function is,

6x^2-24x + 1

a = 6, b = -24, c = 1

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}

=\dfrac{24\pm \sqrt{576-24}}{12}

=\dfrac{24\pm \sqrt{552}}{12}

=\dfrac{24\pm 2\sqrt{138}}{12}

=\dfrac{12\pm \sqrt{138}}{6}

=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}

4 0
3 years ago
I don’t know if this is correct , please help !!!!!! Will mark brainliest !!!!!!!!!!!!
Arisa [49]

Answer:

change the negative to not domain and the zero to in domain

Step-by-step explanation

7 0
3 years ago
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