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Mariulka [41]
3 years ago
11

Which transformations will produce similar, but not congruent, figures?

Mathematics
2 answers:
Kitty [74]3 years ago
5 0

In first three options you are talking about , rotation , Translation and Reflection . When you take these qualities into consideration about a triangle neither the shape , nor size of image changes after Rotation, Translation, and Reflection.

So , First three options are incorrect.

And Fourth option→→→ Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle T"U"V"  produces similar figures, which are not congruent.

→T U V ~ T" U" V"→→→→ When Dilation is done two figures are similar. Because in Dilation Either Preimage stretches or Shrank .The Resulting Image is Similar to Preimage.

Elena-2011 [213]3 years ago
3 0
The answer is D or <span>Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle T"U"V" . I just took the test and I hope I helped : )</span>
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Since <em>x</em> is the number of 14-year periods, the first thing we do is divide 28 years by 14. 28/14=2.  Now we use that in our function, y=55*2^x.

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3 years ago
Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form
ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

\frac{n!}{n1!*n2!*...*nk!}

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

\frac{10!}{2!*2!*2!*2!*2!}=113,400

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

\frac{10!}{2!*2!*3!*3!}=25,200

So, If each team has either two or three students, The number of ways  form teams are:

113,400 + 25,200 = 138,600

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3 years ago
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