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Mariulka [41]
3 years ago
11

Which transformations will produce similar, but not congruent, figures?

Mathematics
2 answers:
Kitty [74]3 years ago
5 0

In first three options you are talking about , rotation , Translation and Reflection . When you take these qualities into consideration about a triangle neither the shape , nor size of image changes after Rotation, Translation, and Reflection.

So , First three options are incorrect.

And Fourth option→→→ Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle T"U"V"  produces similar figures, which are not congruent.

→T U V ~ T" U" V"→→→→ When Dilation is done two figures are similar. Because in Dilation Either Preimage stretches or Shrank .The Resulting Image is Similar to Preimage.

Elena-2011 [213]3 years ago
3 0
The answer is D or <span>Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle T"U"V" . I just took the test and I hope I helped : )</span>
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2. A university class had two recitation sections. The Monday recitation had 64 students and
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22

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Moving 22 students to Monday will result in equal number of students.

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3 years ago
Form a paragraph proof for the following. Make sure you include all the
timama [110]

Answer:

Line BD is Congruent to Line BD due to the Reflexive property. Angle Bad is congruent to angle BCD because of the third angle theorem therefore triangle ABD is congruent to triangle CBD because all angles and sides are congruent

I don't know if that will satisfy your teacher because some prefer different things but that leaves no ground to be inferred and explains everything word for word.

8 0
3 years ago
The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning ca
Fed [463]

Answer:

Sam had a finish time with a z-score of -2.93.

Karen had a finish time with a z-score -1.91.

Sam had the more convincing victory.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Sam:

The mean finish time for a yearly amateur auto race was 186.94 minutes with a standard deviation of 0.372 minute. The winning car, driven by Sam, finished in 185.85 minutes.

So \mu = 186.94, \mu = 0.372, X = 185.85

Z = \frac{X - \mu}{\sigma}

Z = \frac{185.85 - 186.94}{0.372}

Z = -2.93

Sam finishing time was 2.93 standard deviations below the mean.

Sam had a finish time with a z-score of -2.93.

Karen:

The previous year's race had a mean finishing time of 110.7 with a standard deviation of 0.115 minute. The winning car that year, driven by Karen, finished in 110.48 minutes.

So \mu = 110.7, \sigma = 0.115, X = 110.48

Z = \frac{X - \mu}{\sigma}

Z = \frac{110.48 - 110.7}{0.115}

Z = -1.91

Karen finishing time was 1.91 standard deviations below the mean.

Karen had a finish time with a z-score -1.91.

Who had the more convincing victory?

Sam finishing time was 2.93 standard deviations below the mean.

Karen finishing time was 1.91 standard deviations below the mean.

Sam finished more standard deviations below the mean than Karen, that is, he was faster relative to his competition than Karen.

So Sam had the more convincing victory.

8 0
3 years ago
A graduated cylinder actually contains 7.5 mm of water 1/2 measures the volume of the water inside the graduated cylinder is mea
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Answer:

6.667%

Step-by-step explanation:

Given that:

Actual measurement = 7.5 mm

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Percentage error :

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(Actual measurement - measured value)

Error = 7.5 - 7 = 0.5 mm

Percentage error = (0.5 / 7.5) * 100%

Percentage error = 0.0666666 * 100%

= 6.667%

7 0
3 years ago
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