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WINSTONCH [101]
3 years ago
9

Five years ago, a survey found that the proportion of city employees who commute to work by car is 8%. A local city commissioner

claims that the percentage is higher than it was five years ago. Data on employee commuting by car was collected on a random sample of 1000 employees and found 12% of employees commute by car. Test an appropriate hypothesis and state your conclusion at the 10% level of significance.
Mathematics
1 answer:
Mama L [17]3 years ago
4 0

Answer:

The data shows a proportion in car commuting greater than 8%

Step-by-step explanation:

Five years ago, a survey found that the proportion of city employees who commute to work by car is 8%.

Claim : . A local city commissioner claims that the percentage is higher than it was five years ago.

H_0:p=0.08\\H_a:p>0.08

A random sample of 1000 employees was collected

n = 1000

They found 12% of employees commute by car.

No. of employees commute by car = \frac{12}{100} \times 1000=120

We will use one sample proportion test  

x= 120

n = 1000

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{120}{1000}

\widehat{p}=0.12

Formula of test statistic =\frac{\widehat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}

                                       =\frac{0.12-0.08}{\sqrt{\frac{0.08(1-0.08)}{1000}}}

                                       =4.66

Significance level = 10%

α=0.1

Z_{0.10}=1.28(Using z table)

So, test statistic i.e.Z calculated > Z critical

So, we failed to accept null hypothesis .The data shows a proportion in car commuting greater than 8%

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3 years ago
Please help me i need an answer
ivolga24 [154]
I conclude it is C 25.
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3 years ago
Which of the following equations is written in standard form ? A. 2.5x+3=12 B. -10x-3=1 C. 2x+3=12 D. 5x+5y=10
muminat
D. 5x+5y=10

The other 3 could be simplified further and have no y value.

Hope that helps
8 0
3 years ago
253,248,243, find the 49th term.
denpristay [2]

Answer:

13

Step-by-step explanation:

the difference is -5

  • nth=a+(n-1)d
  • a=253,n=49,d=5
  • 253+(49-1)×-5
  • 253+48×-5
  • 253+(-240)
  • 253-240=13

the 49th term is 13

8 0
2 years ago
Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle encl
katovenus [111]

Answer:

The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units

Step-by-step explanation:

The given parameters in the question are;

The radius of the circle, r = 11

The length of the chord PL = 16

The measure of angle ∠PAL = 93°

The segment of the circle for which the area is required = Minor segment PL

The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL

The area of a segment of a circle is given by the following formula;

Area of segment = Area of the sector - Area of the triangle

In detail, we have;

Area of segment = Area of the sector of the circle that contains the segment) - (Area of the isosceles triangle in the sector)

Area of a sector = (θ/360)×π·r²

Where;

r = The radius of the circle

θ = The angle of the sector of the circle

Plugging in the the values of <em>r</em> and <em>θ</em>, we get;

The area of the sector enclosed by arc PL and radii AP and AL = (93°/360°) × π × 11² ≈ 98.2 square units

Area of a triangle = (1/2) × Base length × Height

Therefore;

The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units

∴ The area of the segment PL ≈ (98.2 - 60.58) square units = 37.62 square units

Therefore, the area of the shaded segment PL ≈ 37.62 square units

More examples on area of a shaded segment can be found here:

brainly.com/question/22599425

8 0
2 years ago
Read 2 more answers
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