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3 years ago

9

PLEASE HELP ASAP I REALLY NEED IT

2 answers:

34kurt3 years ago

4 0

Answer: 416

Step-by-step explanation:

The area of a trapezoid is h(a+b)/2. So 16(14+38)/2 = 416

yanalaym [24]3 years ago

4 0

Answer:416 square centimeters

Step-by-step explanation:

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6 2/5 x 1 7/8 x 7/12=

andrey2020 [161]

7 the awnser is 7 ok(kkkkk

3 0

3 years ago

Need Help on math question <br><br>

Nikitich [7]

Answer:

36 yards

Step-by-step explanation:

The triangle is a 3-4-5 right triangle with a scaling factor of 12. No complicated Pythagorean theorem has to be used in this case.

60/12 = 5

48/12 = 4

3 is the only base number remaining.

3(12) =36

4 0

3 years ago

Simplify (3^-2) ^4 what is it

Lana71 [14]

Answer:

1/6561

Step-by-step explanation:

3^-2 = 1/9

1/9^4 = 1/6561

5 0

3 years ago

Read 2 more answers

ΔCAR has coordinates C (2, 4), A (1, 1), and R (3, 0). A translation maps point C to C' (3, 2). Find the coordinates of A' and R

shutvik [7]

Answer:

$A'= (2,-1)$ and $R'=(4,-2)$ under this translation.

Step-by-step explanation:

A translation in $R^{2}$ is a mapping T from $R^{2}$ to $R^{2}$ defined by $T(x,y) = (x + v_1,y+v_2)$ , where $v=(v_1,v_2)$ is a fixed vector in $R^{2}$ .

From the problem we know that $T(2,4)=(3,2)$ , so we need to find the values $v_1$ and $v_2$ such that $T(2,4) = (2 + v_1,4+v_2)=(3,2)$ , so $3=2 + v_1$ and $4+v_2=2$ , thus $v_1=1$ and $v_2=2$ .

Then $T(x,y) = (x + 1,y-2)$ and

$T(1,1)=(1+1,1-2)=(2,-1)=A'$

$T(3,0)=(3+1,0-2)=(4,-2)=R'$

Therefore $A'= (2,-1)$ and $R'=(4,-2)$ . The triangles CAR and C'Q'R' are shown in the figure below.

7 0

3 years ago

PLEASE HELP ANSWER ASAP

Solnce55 [7]

I cant help you on this if there is no coefficients.

3 0

3 years ago