4 years ago

Solve for -2<-3-3x<0

1 answer:

8 0

-3 from all ends to get 1<-3x<3 then divide by -3 on all ends to get -1/3>x>-1 you flip the sign because of the negative,

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What are the solutions to the equation 2x^2 + 9x =5

Maksim231197 [3]

Answer:

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Step-by-step explanation:

$2x^2 + 9x =5$

we have to move 5 in the other side with a different sign, to get a 2 grade ecuation

$2x^2 + 9x -5= 0$

now we know

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we have to find delta

$\boxed{\Delta=b^2-4ac} \\\\ \Delta=9^2-4\cdot2\cdot(-5)\\ \Delta=81+40 \\ \Delta=121$

and now we have to use the formula to find the root square

$\displaystyle \boxed{ X_{1,2}=\frac{-b\pm\sqrt{\Delta} }{2a} }$

$\displaystyle X_1=\frac{-b-\sqrt{\Delta} }{2a} =\frac{-9-11}{2\cdot2}=\frac{-20}{4} =-5$

$\displaystyle X_2=\frac{-b+\sqrt{\Delta} }{2a} =\frac{-9+\sqrt{121} }{2\cdot4} =\frac{-9+11}{4} =\frac{2}{4} =\frac{1}{2}$

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