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3 years ago

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Simplify: 20 sin(2x) cos(2x)

1 answer:

alexandr1967 [171]3 years ago

8 0

Use the the double angle formula:
sin(2A)=2sin(A)cos(A)

substitute 2x for A, then
20sin(2x)cos(2x)=10(sin(2(2x))cos(2(2x))=10sin(4x)

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(PLSSSS HELP) Determine which three out of the six points shown below are a solution to the equation x-3y=22 Plot the three poin

algol [13]

Answer:

$(-2,8)$ $(7,5)$ $(1,7)$

Step-by-step explanation:

Given

$x + 3y = 22$

Solving (a): The possible coordinates

We have:

$(x,y) = (-2,8)$

This gives:

$x + 3y = 22 \to -2 + 3 * 8$

$x + 3y = 22 \to -2 + 24$

$x + 3y = 22 \to 22$

<em>(-2,8) is a point on the grid</em>

$(x,y) = (7,5)$

This gives:

$x + 3y = 22 \to 7 + 3 * 5$

$x + 3y = 22 \to 7 + 15$

$x + 3y = 22 \to 22$

<em>(7,5) is a point on the grid</em>

$(x,y) = (-5,5)$

This gives:

$x + 3y = 22 \to -5 + 3 * 5$

$x + 3y = 22 \to -5 + 15$

$x + 3y = 22 \to 10$

<em>(-5,5) is a not point on the grid</em>

<em></em>

$(x,y) = (1,3)$

This gives:

$x + 3y = 22 \to 1 + 3 * 3$

$x + 3y = 22 \to 1 + 9$

$x + 3y = 22 \to 10$

<em>(1,3) is a not point on the grid</em>

$(x,y) = (1,7)$

This gives:

$x + 3y = 22 \to 1 + 3 * 7$

$x + 3y = 22 \to 1 + 21$

$x + 3y = 22 \to 22$

(1,7) is a point on the grid

So, we plot the following on the grid

$(-2,8)$ $(7,5)$ $(1,7)$

See attachment

8 0

3 years ago

Divide 72k in a ratio of 1:3:5

larisa [96]

1:3:5
firstly u need to find out how much one will get so u will add all the ratios 1:3:5 and divide by 72k(72000) so you will get 8000
therefore 1 will get 8000
3 will get 8000 multiply by 3 =24000
5 will get 8000 multiply by 5 = 40000
do you understand......if you need any more help ...feel free!!!!

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3 years ago

-7(v + 5) = 35 help

Airida [17]

Answer:

v=0

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Does anyone know what to do

klasskru [66]

ok, we need to factor the expression

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3 years ago

Olive sold $6,000 worth of tickets to the game and spent $25 per person on catering. If she made a profit of $4,000, how many pe

erma4kov [3.2K]

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