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astraxan [27]
3 years ago
15

Does anyone know what to do

Mathematics
1 answer:
klasskru [66]3 years ago
4 0

ok, we need to factor the expression

{y}^{5}  - 2 {y}^{4}  - cxy + 6x =  {y}^{4} (y - 2) - x(cy - 6)

since the expression divisible by y-2, then

cy - 6 = k(y - 2)

since 6=2k, then k=c=3

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What is 30 less than 4 times a number is equal to 14
Genrish500 [490]
The answer is x=11
4x-30=14
You add 30 to each side=4x=44
Then you divide 44 by 4 which=11
4 0
3 years ago
x to the fourth power plus 6x to the third power minus 7x squared minus 24x plus 12 over x squared minus 4 ling division
Elden [556K]
X squared plus 6x minus 3
3 0
3 years ago
Kilo typed 1,125 words in 15 minutes let w represent the number of words typed each minute If Lolo typed the same number of word
Alborosie

Answer:

She type <u>75 words</u> in 1 minute.

Step-by-step explanation:

Given:

Lolo typed 1,125 words in 15 minutes.

Let w represent the number of words typed each minute.

Now, to find the number of words she type in 1 minute if Lolo typed the same number of words each minute.

So, we solve it by using cross multiplication method:

<u><em>As 1125 words is equivalent to 15 minutes.</em></u>

<u><em>Thus, w number of words equivalent to 1 minutes</em></u>.

\frac{1125}{15} =\frac{w}{1}

By cross multiplying we get:

⇒ 1125=15w

<em>Dividing both sides by 15 we get:</em>

⇒ 75=w

⇒ w=75.

Therefore, she type 75 words in 1 minute.

4 0
3 years ago
A 40-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and the chain
daser333 [38]

Answer:

a) W₁ = 78400 [J]

b)Wt = 82320 [J]  

Step-by-step explanation:

a) W = ∫ f*dl      general expression for work

If we have a chain with density of 10 Kg/m, distributed weight would be

9.8 m/s² * 10 kg   = mg

Total length of th chain is 40 m, and the function of y at any time is

f(y) = (40 - y ) mg   where ( 40 - y ) is te length of chain to be winded

At the beggining we have to wind 40 meters   y = 0 at the end of the proccess  y = 40 and there is nothing to wind then:

f(y) = mg* (40 - y )

W₁ =  ∫f(y) * dy    ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy  ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy

W₁ = mg [ 40*y |₀⁴⁰   -  1/2 * y²  |₀⁴⁰    ⇒  W₁ = mg* [ 40*40 - 1/2 (40)² ]

W₁ = mg * [1/2]     W₁ = 10*9,8* ( 800 )

W₁ = 78400 [J]

b) Now we can calculate work to do if we have a 25 block and the chain is weightless

W₂ = ∫ mg* dy     ⇒    W₂  = ∫₀⁴⁰ mg*dy   ⇒    W₂  = mg y |₀⁴⁰

W₂ = mg* 40   = 10*9.8* 40  

W₂ = 3920 [J]

Total work

Wt = W₁  +  W₂        ⇒    Wt = 78400 + 3920

Wt = 82320 [J]

6 0
3 years ago
I need help with number 14
strojnjashka [21]
The ionic compound produced would be Aluminum Oxide or Al2O3.

- The answer is C
7 0
3 years ago
Read 2 more answers
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