Answer:
There are more nutrients available in estuaries. There are more nutrients available in estuaries.
Explanation:
at equilibrium.
<h3>Explanation</h3>
Concentration for each of the species:
There was no Y to start with; its concentration could only have increased. Let the change in be .
Make a table.
Two moles of X will be produced and two moles of Z consumed for every one mole of Y produced. As a result, the <em>change</em> in will be and the <em>change</em> in will be .
.
Add the value in the C row to the I row:
.
What's the equation of for this reaction? Raise the concentration of each species to its coefficient. Products go to the numerator and reactants are on the denominator.
.
. As a result,
.
.
The degree of this polynomial is three. Plot the equation on a graph and look for any zeros. There's only one zero at . All three concentrations end up greater than zero.
Hence the equilibrium concentration of Y: .
Answer:
Final mass = 159.5 g
Final temperature = 10 C
Final density = 1.00 g/ml
Explanation:
<u>Given:</u>
Beaker 1:
Mass of water = 44.3 g
Temperature = 10 C
Beaker 2:
Mass of water = 115.2 g
Temperature = 10 C
Density of water at 10C = 1.00 g/ml
<u>To determine:</u>
The final mass, temperature and density of water
<u>Calculation:</u>
Since there is no change in temperature, the final temperature will be 10 C
Density of a substance is an intensive property i.e. it is independent of the mass. Hence the density of water will remain constant i.e. 1.00 g/ml
Answer: A plot of the natural log of the concentration of the reactant as a function of time is linear.
Explanation:
Since it was explicitly stated in the question that the half life is independent of the initial concentration of the reactant then the third option must necessarily be false. Also, the plot of the natural logarithm of the concentration of reactant against time for a first order reaction is linear. In a first order reaction, the half life is independent of the initial concentration of the reactant. Hence the answer.