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Veseljchak [2.6K]
3 years ago
11

A chemical reaction is expected to produce 0.068 moles of oxygen. What volume in liters will be occupied by this gas sample at 2

73K and 1 atm?​
Chemistry
1 answer:
poizon [28]3 years ago
6 0

Answer: 1.22 litres

Explanation: in STP conditions amount of substance n= V/Vm

Vm is molar volume of gas, 22.41 litres/ mole.

Volume V = n·Vm= 0.068 mol·22.41 l / mol= 1.52388 litres

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nikklg [1K]

Answer:

CH3OH and NADH

Explanation:

The given chemical reaction is an redox reaction in which reduction and oxidation take place.

In the process of oxidation: electrons are loss while in the process of reduction: electrons are gained.

In the given redox reaction: CH3OH + NAD --> CH2O + NADH

NAD is reduced to NADH as NADH gains one hydrogen electron while CH3OH (methanol) is oxidized to CH2O (methanal)  by losing electrons.

So, CH3OH (methanol) and NADH are the reduced forms while NAD and CH2O (methanal) are oxidized forms.

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What is the molecular geometry of PBr3? A. trigonal pyramidal B. trigonal planar C. linear D....
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How many grams of oxygen are required too burn 8.8g of c3h8?
hichkok12 [17]
From the balanced equation: 
<span>1mol C3H8 requires 5mol O2 for combustion </span>
<span>Molar mass C3H8 = 44g/mol </span>
<span>8.8g C3H8 = 8.8/44 = 0.2mol C3H8 </span>
<span>This will require 5*0.2 = 1.0mol O2 </span>
<span>Molar mass O2 = 32g/mol </span>
<span>Therefore 32g of O2 required.


</span>
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Technetium-104 has a half life of 18.0 minutes. how much of a 165.0 g sample remains after 90.0 minutes?
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The mass of 165.0 g sample that remains after 90.0 minutes is 5.16 grams

calculation

lambda㏑2/18= 0.0385

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8 0
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