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2 years ago

Which statement best describes a chemical property of Iron?

Chemistry

2 answers:

Karo-lina-s [1.5K]2 years ago

4 0

Answer:

I think it is iron conducts electricity and heat

mina [271]2 years ago

3 0

Answer:

C. Iron combines with oxygen to form rust.

Explanation:

The correct answer is "C" because it refers to the ability to rust, a chemical property, because rusting is a chemical change.

Answer choice "A" is incorrect because it refers to malleability, the ability to be flattened or pressed into sheets, a physical property. After being flattened, the iron would have gone through a physical change, not chemical.

Answer choice "B" is incorrect because it refers to conductivity, the ability to conduct electricity and heat, a physical property. The iron does not experience a chemical change while conducting.

Answer choice "D" is incorrect because it refers to ductility, the ability to be made into wire, a physical property. The iron is not going through a chemical change as wire.

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A 2.5 mol sample of phosphorus pentachloride, PCl5 dissociates at 160C and 1.00atm to give 0.338 mol of phosphorus trichloride a

Readme [11.4K]

Explanation:

Moles of phosphorus pentachloride present initially = 2.5 mol

Moles of phosphorus trichloride at equilibrium = 0.338 mol

$PCl_5\rightleftharpoons PCl_3+Cl_2$

Initially

2.5 mol 0 0

At equilibrium:

(2.5 - x) mol x x

So, from above, the moles of phosphorus trichloride at equilibrium , x= 0.338 mol

Mass of 0.338 moles of phosphorus trichloride at equilibrium:

= 0.338 mol × 137.5 g/mol = 46.475 g

Moles of phosphorus pentachloride present at equilibrium :

= (2.5 - 0.338) mol = 2.162 mol

Mass of 2.162 moles of phosphorus pentachloride at equilibrium:

= 2.162 mol × 208.5 g/mol = 450.777 g

Moles of chloride gas present at equilibrium : 0.338 mol

Mass of 0.338 moles of chloride gas at equilibrium:

= 0.338 mol × 71 g/mol = 23.998 g

3 0

3 years ago

The range in size of most atomic radii is approximately what?

Nastasia [14]

It is approximately 10 ^ -10

3 0

3 years ago

balloon filled with water is places in a microwave until it bursts. Name two different physical changes that occur during this r

Kisachek [45]

Answer:

dont know

Explanation:

3 0

3 years ago

Read 2 more answers

A chemist wishing to do an experiment requiring 47-Ca2+ (half-life = 4.5 days) needs 5.0 μg of the nuclide. What mass of 47-CaCO

NARA [144]

Answer:

5.8μg

Explanation:

According to the rate or decay law:

N/N₀ = exp(-λt)------------------------------- (1)

Where N = Current quantity, μg

N₀ = Original quantity, μg

λ= Decay constant day⁻¹

t = time in days

Since the half life is 4.5 days, we can calculate the λ from (1) by substituting N/N₀ = 0.5

0.5 = exp (-4.5λ)

ln 0.5 = -4.5λ

-0.6931 = -4.5λ

λ = -0.6931 /-4.5

=0.1540 day⁻¹

Substituting into (1) we have :

N/N₀ = exp(-0.154t)----------------------------- (2)

To receive 5.0 μg of the nuclide with a delivery time of 24 hours or 1 day:

N = 5.0 μg

N₀ = Unknown

t = 1 day

Substituting into (2) we have

[5/N₀] = exp (-0.154 x 1)

5/N₀ = 0.8572

N₀ = 5/0.8572

= 5.8329μg

≈ 5.8μg

The Chemist must order 5.8μg of 47-CaCO3

6 0

2 years ago

Consider the reaction: CaCO3(s) à CaO(s) + CO2(g)

Vsevolod [243]

Answer:

131.5 kJ

Explanation:

Let's consider the following reaction.

CaCO₃(s) → CaO(s) + CO₂(g)

First, we will calculate the standard enthalpy of the reaction (ΔH°).

ΔH° = 1 mol × ΔH°f(CaO(s)) + 1 mol × ΔH°f(CO₂(g) ) - 1 mol × ΔH°f(CaCO₃(s) )

ΔH° = 1 mol × (-634.9 kJ/mol) + 1 mol × (-393.5 kJ/mol) - 1 mol × (-1207.6 kJ/mol)

ΔH° = 179.2 kJ

Then, we calculate the standard entropy of the reaction (ΔS°).

ΔS° = 1 mol × S°(CaO(s)) + 1 mol × S°(CO₂(g) ) - 1 mol × S°(CaCO₃(s) )

ΔS° = 1 mol × (38.1 J/mol.K) + 1 mol × (213.8 J/mol.K) - 1 mol × (91.7 J/mol.K)

ΔS° = 160.2 J/K = 0.1602 kJ/K

Finally, we calculate the standard Gibbs free energy of the reaction at T = 25°C = 298 K.

ΔG° = ΔH° - T × ΔS°

ΔG° = 179.2 kJ - 298 K × 0.1602 kJ/K

ΔG° = 131.5 kJ

6 0

3 years ago