Answer:
Step-by-step explanation:
p=,
(22+6)2-21=
44+12-21=
35=,
If you factor out the equation, you get that 35=4p(if you factor it out)
Therefore,
Answer:
f) Not possible
Step-by-step explanation:
The triangles can be shown to be similar by SAS, but the corresponding sides are not marked as congruent. With the given information, it is not possible to show the triangles are congruent.
Answer: -9
Step-by-step explanation: it is a negative because it is minus 9$ from the price just like adding -9
Answer:
A
Step-by-step explanation:
We want to find the surface area, which will essentially just be the areas of all the figures given in the net.
We have two congruent triangles and 3 different rectangles.
<u>Triangles</u>:
The area of a triangle is denoted by: A = (1/2) * b * h, where b is the base and h is the height. The base here is 3 and the height is 4, so:
A = (1/2) * b * h
A = (1/2) * 3 * 4 = 6
Since there are two triangles, multiply 6 by 2: 6 * 2 = 12 cm squared
<u>Rectangles</u>:
The area of a rectangle is denoted by: A = b * h, where b is the base and h is the height.
The base of the leftmost rectangle is 4 and the height is 7, so:
A = b * h
A = 4 * 7 = 28
The base of the middle rectangle is 3 and the height is 7, so:
A = b * h
A = 3 * 7 = 21
The base of the rightmost rectangle is 5 and the height is 7, so:
A = b * h
A = 5 * 7 = 35
Add these together:
12 + 28 + 21 + 35 = 96 cm squared
The answer is thus A.
In both cases there are more than one possible function sutisfying given data.
1. If
- x‑intercepts are (–5, 0), (2, 0), and (6, 0);
- the domain is –5 ≤ x ≤ 7;
- the range is –4 ≤ y ≤ 10,
then (see attached diagram for details) you can build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their maximum and minimum left and right you can obtain another function that satisfies the conditions above.
2. If
- x‑intercepts are (–4, 0) and (2, 0);
- the domain is all real numbers;
- the range is y ≥ –8,
then you can also build infinetely many functions. From the diagram you can see two graphs: first - blue graph, second - red graph. Translating their minimum left and right you can obtain another function that satisfies the conditions above.
Note, that these examples are not unique, you can draw a lot of different graphs of the functions.
Answer: yes, there are more than one possible function