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2 years ago

Math question please !!!

Mathematics

2 answers:

aalyn [17]2 years ago

8 0

in the table y is increased 70 for every 1 in x (210/3 = 70) on the graph for every 1 increase on x y increases by 55 (110/2 = 55) so for the graph for x = 11, y =55 x 11 = 605 for the table for x = 11, y = 11*70 = 770 the difference is 770-605 = 165 the 2nd answer is the correct one.

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Verdich [7]2 years ago

5 0

In the table y is increased 70 for every 1 in x (210/3 = 70) on the graph for every 1 increase on x y increases by 55 (110/2 = 55) so for the graph for x = 11, y =55 x 11 = 605 for the table for x = 11, y = 11*70 = 770 the difference is 770-605 = 165 the 2nd answer is the correct one.

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The volume of a cubical box is 474.552m3.Find the length of each side of the box

Cerrena [4.2K]

The formula of a volume of a cube:

$V=a^3$

We have $V=474.552\ m^3$

Substitute:

$a^3=474.552\to a=\sqrt[3]{474.552}\\\\a=7.8\ m$

Answer: The length of each side of the box is equal 7.8 m.

8 0

2 years ago

BRAINEST IF YOU GET THSI RIGHT

Scorpion4ik [409]

<h3>Solution :</h3>

$\sf \dfrac{6x+4}{3} = \dfrac{5x-5}{8}$

By cross multiply, we get

$\sf : \implies (6x+4) \times 8 = (5x-5) \times 3$

$\sf : \implies 48x+32 = 15x-15$

$\sf : \implies 48x+32 - 15x + 15= 0$

$\sf : \implies 33x + 47 = 0$

$\sf : \implies 33x = -47$

$\sf : \implies x = \dfrac{- 47}{33}$

Therefore, answer is $\sf x = \dfrac{- 47}{33}$

4 0

2 years ago

Read 2 more answers

What is the fraction -2 over 3 multiplied by -2 equal?

defon

-2/3 times -2. You change -2 into -2/1 so you can multiply numerator to numerator and denominator to denominator. You will get 4/3 (negatives cancel out)

3 0

2 years ago

How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .