Answer:
D) 1/36
Step-by-step explanation:
You are trying to roll a 3 the first time, and then a 5 the second time. This means that order matters.
It is given to you, that you are rolling a standard die (6-sides). The dice is ordered in the following: 1, 2, 3, 4, 5, 6
The first time, you are rolling for a 3. Note that there is only one 3 in the sequence, so your chance of rolling a 3 is 1 out of 6: 1/6.
The second time, you are rolling for a 5. Note that there is only one 5 in the sequence, so your chance of rolling a 5 is 1 out of 6: 1/6.
Next, multiply the two fractions together to find the probability of rolling a 3 and then a 5:
1/6 x 1/6 = (1 x 1)/(6 x 6) = 1/36
D) 1/36 is your answer.
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Answer:
x=2, y=-1, z=3
Step-by-step explanation:
The system shown in the attached picture can be solved using any method you wish
I think that the best way to go is by using the subtraction method,
First multiply the equation x+y+z=4 by 2, then sum it to the second equation.
This gives another equation: 4x+z=11.
If we subtract the first eq. with the third, we have another eq. -5x+z=-7.
Lest sum the 2 new founded equations, to obtain the following result: -9x=-18
thus, we obtain x=2
Next lets go backwards in the prior eq -5x+z=-7, with x=2, we obtain that z=3
Now in the first equation (x+y+z=4) we can substitute x=2, z=3 to obtain y value.
Hello,
(3+2i)*x=17+7i
==>x=(17+7i)/(3+2i)
==>x=(17+7i)(3-2i)/((3+2i)(3-2i))
==>x=(65-13i)/13
==>x=5-i