How do you eliminate 6x-12y=24 along with -x-6y=4

1 answer:

5 0

First you need to multiply by a factor that will givr you the same value in one of the x or y value.
(6x-12y=24)1
+(-x-6y=4)-2
6x-12y=24
=2x+12y=-8
8x=16÷8
x=2
now that you have x, substitute x by 2 in one of the eqauations
-2-6y=4
+2. +2
=-6y=6
÷-6. ÷-6
y=-1

You might be interested in

How to do the problem

marta [7]

There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
$8 \frac{1}{4} + 9 \frac{1}{4} + 8 \frac{7}{8} + 9 \frac{5}{8} + 10 \frac{3}{4}$
$= \frac{8 \times 4 + 1}{4} + \frac{9 \times 4 + 1}{4} \\ + \frac{8 \times 8 + 7}{8} + \frac{9 \times 8 + 5}{8} \\ + \frac{10 \times 4 + 3}{4}$
$= \frac{33}{4} + \frac{37}{4} + \frac{71}{8} + \frac{77}{8} + \frac{43}{4} \\ = \frac{33 \times 2}{4 \times 2} + \frac{37 \times 2}{4 \times 2} + \frac{71}{8} \\ + \frac{77}{8} + \frac{43 \times 2}{4 \times 2}$
$= \frac{66 + 74 + 71 + 77 + 86}{8}$
$= \frac{374}{8} = \frac{186}{4}$
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
$\frac{186 - 153}{4} = \frac{33}{4} = 8 \frac{1}{4}$

The leftover watermelon is 8 & 1/4 pounds.

6 0

2 years ago

The lengths of the sides of triangle ABC are represented in terms of the variable m, where m > 6.

Yanka [14]

Answer:

m(C)<m(B)<m(A).

Step-by-step explanation:

1) according to the condition the shortest side is AB, the longest side is BC, the middle is AC. Then

2) the smallest angle is BCA (or C), the middle angle is ABC (or B), the largest angle is BAC (or A).

6 0

2 years ago

What's the awnswer to 10 divided by 2/7?