How do you eliminate 6x-12y=24 along with -x-6y=4

1 answer:

5 0

First you need to multiply by a factor that will givr you the same value in one of the x or y value.
(6x-12y=24)1
+(-x-6y=4)-2
6x-12y=24
=2x+12y=-8
8x=16÷8
x=2
now that you have x, substitute x by 2 in one of the eqauations
-2-6y=4
+2. +2
=-6y=6
÷-6. ÷-6
y=-1

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Rewrite the form In exponential form: Log100 = x

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Answer:

$10^x=100$

Step-by-step explanation:

You know how subtraction is the opposite of addition and division is the opposite of multiplication? A logarithm is the opposite of an exponent. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that $3^2=9$ ; as a logarithm, the exponent gets moved to its own side of the equation, and we write the equation like this: $\log_3{9}=2$ , which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like $\log1000$ uses base 10, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression $\log100=x$ means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is $10^x=100$ .