Step One
Find the base area of the large hexagon as though the smaller one was not removed.
Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.
Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)
Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.
Area of the remaining piece = area of large hexagon - area of the small hexagon
Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)
Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18
I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3
Answer:
Yes, you can
Step-by-step explanation:
As a point of reference, assume the equation is:
Where
and
In standard unit of conversion:
So:
Substitute 0.4793x for x in
The above equation is the equivalent of in quarts
<em>So, irrespective of what the equation is, you can always substitute quarts into the equation.</em>
Step-by-step explanation:
first expand :
6p +36 -p +6
5p+42
$12 is a better deal because u get 2 more ounces for just $4 more.
Hope that is what the answer was supposed to be.
Answer:
Measure of side C is 7.14
Step-by-step explanation:
In this question, we are to find the length of the side C.
To get this, we are to employ the use of the cosine formula.
Mathematically, this is calculated as;
c^2 = a^2 +b^2 - 2ab*cos(C)
Where; a = 10 b = 3 and c = 15 degrees
Plugging these values into the equation, we have;
C^2 = 10^3 + 3^2 -2(3)(10)Cos 15
C^2 = 100 + 9 - 57.96
C^2 = 51.04
C = √(51.04)
C = 7.14
