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den301095 [7]
3 years ago
5

Select all the correct statements.

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
8 0

Answer:

C,D,E,F

Step-by-step explanation:

A amplitude is 2

B period is 4pi

viva [34]3 years ago
7 0

Answer:

f option is write

Step-by-step explanation:

because it is true

mark me brainlist

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Can someone help me please? I don't nderstand this
musickatia [10]

Answer:

perpendicular(p)=5

base(b)=12

hypotenuese(h)=?

using pytha goras theorem,

h^2=P^2+b^2

h^2=(5)^2+(12)^2

h^2=25+144

h^2=169

h^2=13^2

h=13.

6 0
3 years ago
Elton is a candle maker each 15 cm long candle he makes burns evenly for 6 hours
Rom4ik [11]
15cm = 6 hours

45cm = 18 hours

Answer : 18 hours
6 0
3 years ago
Read 2 more answers
Can someone please explain this step by step on how to do it
luda_lava [24]
 addition factors of 44 equivalent to a ratio of 4:7
4*3= 12
7*3= 21
12+21= 32
4*4= 16
4*7= 28
28+16= 44
This is one of those things that you just have to do a bunch of calculations to eliminate and identify by deductive reasoning.
6 0
3 years ago
Use the linear equation 3(x+1)= 3x + 3 to answer parts (a)-(d) Does x = 5 satisfy the equation above
Alexxandr [17]
X would equal 0 because u would use the distribution 3x+3=3x+3 and then subtract three from the three on the other side and then subtract 3x from 3x and then 0
8 0
3 years ago
What is the solution of the equation (x – 5)2 3(x – 5) 9 = 0? use u substitution and the quadratic formula to solve.
Ahat [919]

The value of x in the equation (x-5)^{2} +3(x-5)+9=0is x=(7+3\sqrt{3}i)/2,

(7-3\sqrt{3}i)/2.

Given equation (x-5)^{2} +3(x-5)+9=0 .

We have to find the solution of the equation.

Equation  is solved to find the value of variables. The number of values of the variable depends on the highest power of variables.

let (x-5)=u-------------------1

equation becomes u^{2} +3u+9=0

solution of a quadratic formula

x=-b±\sqrt{b^{2} -4ac}/2a

on comparing with general form a=1,b=3, c=9

u=-3±\sqrt{3^{2} -4*1*9} /2

=-3±\sqrt{9-36}/2

=-3±3\sqrt{-27}/2

=-3±3\sqrt{3} i/2

u_{1} =-3+3\sqrt{3}/2 , u_{2}=-3-3\sqrt{3}/2

put the values of u_{1} in equation 1

x-5=u_{1}

x-5=-3+3\sqrt{3} /2

x=-3+3\sqrt{3}i/2+5

x=7+3\sqrt{3} i/2

put the values of u_{2} in  equation2

x-5=u_{2}

x-5=-3-3\sqrt{3} /2

x=7-3\sqrt{3}/2

Hence the values of x are 7+3\sqrt{3}i/2, 7-3\sqrt{3}i/2.

Learn more about equation at brainly.com/question/2972832

#SPJ4

5 0
2 years ago
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