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Elena L [17]
2 years ago
12

PLZ HELP ASAP!!! A rectangular prism with a volume of 4 cubic units is filled with cubes with side lengths of 1/3 unit. How many

1/3 units cubes does it take to fill the prism?
Mathematics
2 answers:
blsea [12.9K]2 years ago
6 0

Answer:

Hey!

Your answer is 108!

Step-by-step explanation:

I'm so sorry but i did my workings on the sheet and forgot to put it up!!

HOPE THIS HELPS ANYWAYS!!

VashaNatasha [74]2 years ago
5 0

Answer:

<em>Hello There the Correct answer is 192.</em>

<h3> Explanation</h3>

Each cube with side lengths of 1/4 have a volume of (1/4)3 which means each cube's volume is 0.015625 cubic units. To find how many cubes are needed to fill the prism, divide 3 cubic units by 0.015625 cubic units. Your answer will be 192 cubes.

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Please help me<br> 2/3÷(−5/6)
agasfer [191]
I hope this helps you



2/3÷(-5/6)


2/3× -6/5


2×-6/3×5


-12/15


-4/5
3 0
3 years ago
Read 2 more answers
Complete the statement using always, sometimes, or never. A rectangle is __________________ a rhombus.
Lesechka [4]
Hi!

A rectangle can sometimes be a rhombus if it has sides of all equal lengths. If a rectangle was a rhombus, it would also be a square. Furthermore, a square is always a rhombus.

Hope this helps! :)
7 0
3 years ago
Which statement is true​
Wittaler [7]

Answer:

  • The correct answer would be <em>C</em><em> </em>
  • <em>Reason</em><em> </em><em>being</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>angle</em><em> </em><em>stays</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>rotation</em><em> </em>
7 0
3 years ago
PLz help me this is 7th grade math
UkoKoshka [18]

Answer:

g = 118°, h = 62°, k = 140°, m = 40°

Step-by-step explanation:

g = 118°

h = 180 - 118 = 62°

k = 140°

m = 180 - 140 = 40°

5 0
3 years ago
Please give a good answer :)
Alex

Answer:

P(4≤x≤7) = 2/3

Step-by-step explanation:

We'll begin by obtaining the sample space (S) i.e possible outcome of rolling both dice at the same time. This is illustrated below:

1,1 1,2 1,3 1,4 1,5 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,1 3,2 3,3 3,4 3,5 3,6

4,1 4,2 4,3 4,4 4,5 4,6

5,1 5,2 5,3 5,4 5,5 5,6

6,1 6,2 6,3 6,4 6,5 6,6

Adding the outcome together, the sample space (S) becomes:

2 3 4 5 6 7

3 4 5 6 7 8

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

7 8 9 10 11 12

Next, we shall obtain the event of 4≤x≤7. This is illustrated below:

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

Finally, we shall determine P(4≤x≤7). This can be obtained as follow:

Element in the sample space, n(S) = 36

Element in 4≤x≤7, n(4≤x≤7) = 24

Probability of 4≤x≤7, P(4≤x≤7) = ?

P(4≤x≤7) = n(4≤x≤7) / nS

P(4≤x≤7) = 24/36

P(4≤x≤7) = 2/3

4 0
3 years ago
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