Answer:
<h2>The value of a is 12.</h2>
Step-by-step explanation:
The equation is given by (a - 12)x = a + 8.
In order to get the solution of the equation, that is the value of x, the above equation is needs to be divided by a - 12. (a - 12) will be in the denominator.
The solution can not be found, if the value of a - 12 will be 0, that is a = 12.
Step-by-step explanation:
<h3><u>Given :-</u></h3>
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
<h3>
<u>Required To Prove :-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Proof :-</u></h3>
On taking LHS
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
We know that
Tan θ = 1/ Cot θ
and
Cot θ = 1/Tan θ
=> (1+Cot²θ)(1+Tan²θ)
=> (Cosec² θ) (Sec²θ)
Since Cosec²θ - Cot²θ = 1 and
Sec²θ - Tan²θ = 1
=> (1/Sin² θ)(1/Cos² θ)
Since , Cosec θ = 1/Sinθ
and Sec θ = 1/Cosθ
=> 1/(Sin²θ Cos²θ)
We know that Sin²θ+Cos²θ = 1
=> 1/[(Sin²θ)(1-Sin²θ)]
=> 1/(Sin²θ-Sin²θ Sin²θ)
=> 1/(Sin²θ - Sin⁴θ)
=> RHS
=> LHS = RHS
<u>Hence, Proved.</u>
<h3><u>Answer:-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Used formulae:-</u></h3>
→ Tan θ = 1/ Cot θ
→ Cot θ = 1/Tan θ
→ Cosec θ = 1/Sinθ
→ Sec θ = 1/Cosθ
<h3><u>Used Identities :-</u></h3>
→ Cosec²θ - Cot²θ = 1
→ Sec²θ - Tan²θ = 1
→ Sin²θ+Cos²θ = 1
Hope this helps!!
Answer:
d=3
Step-by-step explanation:
so yu do 18+18 and yu get 36 and then you do 43+3 vause that is how muvk the lockers cost
Answer: A. 0.50
Step-by-step explanation:
The formula to find the sample size : 
, where p= Prior estimate of population proportion.
E= Margin of error
z* =Critical z-value.
When , we do not have prior estimate of population proportion , we use p= 0.5 because at p=0.5 it gives the maximum same sample size for the corresponding confidence interval and margin of error.
Therefore , the conservative value for n can be obtained by using p=0.50.
Therefore , the correct answer is A.0.50 .
Answer:
D. 119
Step-by-step explanation:
To find the common difference, we take the second term and subtract the first term
2-(-7) = 9
We check by taking the third term and subtracting the second
11-2 = 9
The common difference is 9
The formula for an arithmetic sequence is
an = a1 +d(n-1)
where a1 is the first term, d is the common difference and n is the number of the term in the sequence
a1=-7, d=9 and we are looking for the 15th term so n=15
a15 = -7 +9(15-1)
a15 = -7+9(14)
=-7 +126
= 119
