All categories

3 years ago

How is locating -1.5 on a number line the same as locating 1.5 on a number line? How is it different?

1 answer:

4 0

It’s the same in the sense that 1.5 and -1.5 are the same distance away from 0 - they have he same *absolute value*. It’s different in *where* you look. 1.5 is 1.5 to the *right* of 0, while -1.5 is 1.5 to the *left* of zero.

You might be interested in

Solve for f. f + 15 < 6 or f + 12 > 16 _

Sergeeva-Olga [200]

Step-by-step explanation:

1. f+15<6

= f<6-15

f < -9

2. f+12 >16

f >16-12

f > 4

5 0

2 years ago

Can I get help on this please

Misha Larkins [42]

Answer:

5. You can round question a up to 100 + 55 (then do the counting)

5. You can round question b up to 245 - 100 (then do the counting)

You can round question c up to 100 x 5 (then do the counting)

You can round question d up to 100 x 20 (then subtract accordingly)

Please rank Brainliest if this helps!

4 0

2 years ago

Find an equation for the inverse for each of the following.

IgorLugansk [536]

Answer:

To solve these first swap x and y, solve for y and name it inverse function

3. y = -8x + 2

x = -8y + 2
8y = -x + 2
y = -x/8 + 2/8
y = -(18)x + 1/4

f⁻¹(x) = -(18)x + 1/4

-----------------------------------------

4. y = (2/3)x - 5

x = (2/3)y - 5
(2/3)y = x + 5
y = (3/2)x + (3/2)5
y = 1.5x + 7.5

f⁻¹(x) = 1.5x + 7.5

-----------------------------------------

5. f(x) = 2x² - 6

x = 2y² - 6
2y² = x + 6
y² = 1/2x + 3
y = $\sqrt{1/2x + 3}$

f⁻¹(x) = $\sqrt{1/2x + 3}$

-----------------------------------------

6. y = (x - 3)²

x = (y - 3)²
$\sqrt{x}$ = y - 3
y = 3 + $\sqrt{x}$

f⁻¹(x) = 3 + $\sqrt{x}$

4 0

2 years ago

Please help Ill give brainy pleas help please -

mars1129 [50]

The answer to this is a=3

4 0

1 year ago

Benny bought nine new baseball trading cards to add to his collection. The next day his dog ate half of his collection. There ar

hjlf

9+x

divided by

x=61

3 0

2 years ago

Read 2 more answers