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Liono4ka [1.6K]
3 years ago
6

What is the inverse of f(x)=(2x−4)2 for x≥2 where function g is the inverse of function f?

Mathematics
1 answer:
Brrunno [24]3 years ago
3 0

Answer:

you have to multiply two variables to get the first variable that not the complete question.

Step-by-step explanation; f(x)=(2x-4)

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For the graph, identify the axis of symmetry, vertex, y-intercept, max/min, and domain and range
kirill [66]

In the present problem, it is presented a figure of a graph of a parabola with concavity facing up, what implies in that the graph will not have a Max., but a Min. value, and it is in the vertex.

Let us start with the A.O.S. (Axis Of Symmetry). For a parabola, it is the line that passes in the minimum point, that can be identified in the present figure as being in the x = - 1 point. And for this reason, we are able to answer the first part as:

A.O.S.: x = -1

Now, as mentioned above, the vertex lies in the minimum point, which is located in the x = -1 and with height y = 2. This allow us to answer the second part as:

Vertex: (-1, 2)

About the y-interception, it happens when the graph passes through the y-axis. It happens when x = 0, and the answer is just the value of Y where the graph assumes x=0, which is at:

Y-intercept: y = 4

Because the parabola has concavity facing up, the graph presents a value of minimum, but no maximum. And this is possible to be identified as the point where x = -1 and y = 2, which lead us to the following answer for the third part of the question:

Min.: (-1 , 2)

The domain for any second-order polynomial is the entire real number because there is no restriction for the value of x. And for this reason, the answer of the fourth part of the answer is:

Domain: All real numbers

About the range, for a parabola with the concavity facing up, it can be determined as all the real numbers bigger or equal to the minimum value of the function, which is y = 2. From this reason, we are able to answer the last part of the question as:

Range: All real numbers ≥ 2
8 0
1 year ago
a baseball dropped from the roof of a tall building takes 3.1 seconds to hit the ground. how tall is the building?
cluponka [151]
Initial velocity = 0 m/s
Acceleration = 9.8 m/s²
Time = 3.1 s

s = ut + 1/2 at²
s = 1/2 x 9.8 x 3.1²
s = 47.1 m

The building is 47.1 meters tall
4 0
3 years ago
Read 2 more answers
Evaluate 4x2 +3 when x=5
Molodets [167]

Answer:

103

Step-by-step explanation:

We substitute x with 5:

4(5)^2+3

Solve the exponent first:

5^2 = 25

<em>Note: We are using order of operations (consecutively)</em>

  1. <em>Parentheses </em>
  2. <em>Exponents</em>
  3. <em>Multiplication</em>
  4. <em>Division</em>
  5. <em>Addition </em>
  6. <em>Subtraction</em>

Multiply:

25 * 4 = 100

Add:

100 + 3 = 103

Our answer is 103

<em />

7 0
3 years ago
Read 2 more answers
An advertisement for a popular weight-loss clinic suggests that participants in its new diet program lose, on average, more than
Sedbober [7]

Testing the hypothesis, it is found that:

a)

The null hypothesis is: H_0: \mu \leq 10

The alternative hypothesis is: H_1: \mu > 10

b)

The critical value is: t_c = 1.74

The decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

c)

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

Item a:

At the null hypothesis, it is tested if the mean loss is of <u>at most 10 pounds</u>, that is:

H_0: \mu \leq 10

At the alternative hypothesis, it is tested if the mean loss is of <u>more than 10 pounds</u>, that is:

H_1: \mu > 10

Item b:

We are having a right-tailed test, as we are testing if the mean is more than a value, with a <u>significance level of 0.05</u> and 18 - 1 = <u>17 df.</u>

Hence, using a calculator for the t-distribution, the critical value is: t_c = 1.74.

Hence, the decision rule is:

  • If t < 1.74, we <u>do not reject</u> the null hypothesis.
  • If t > 1.74, we <u>reject</u> the null hypothesis.

Item c:

We have the <u>standard deviation for the sample</u>, hence the t-distribution is used. The test statistic is given by:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • s is the standard deviation of the sample.
  • n is the sample size.

For this problem, we have that:

\overline{x} = 10.8, \mu = 10, s = 2.4, n = 18

Thus, the value of the test statistic is:

t = \frac{\overline{x} - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{10.8 - 10}{\frac{2.4}{\sqrt{18}}}

t = 1.41

Since t = 1.41 < 1.74, we <u>do not reject the null hypothesis</u>, that is, it cannot be concluded that the mean weight loss is of more than 10 pounds.

A similar problem is given at brainly.com/question/25147864

3 0
3 years ago
Using the discriminatory, determine the number of real solution 2x^2+7x-15=0
Scilla [17]

Answer:

c. two real solutions

Step-by-step explanation:

x = -5 , x = 1.5

6 0
3 years ago
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