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4 years ago

1. 11 1/6 =? 2. 2 9/10 =? 3. - 4/12 =? Please help me

Mathematics

1 answer:

Jobisdone [24]4 years ago

4 0

Answer:

1.Exact Form: 67/6

Decimal Form: 11.167

Mixed Number Form: 11 1/6

2. 2 9/10

3. Exact Form: −1/3

Decimal Form: −0.3333

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How many cubes with side lengths of

liq [111]

The number of 1/3 cm-cubes that would fill the rectangular prism is approximately 20 cubes.

<h3>What is the Volume of a Cube?</h3>

Volume = a³, where a is the side length.

<h3>What is the Volume of a Rectangular Prism?</h3>

Volume = lwh

Given the following:

a = ⅓ cm
l = 4/2 cm = 1/2 cm
w = 2/2 cm = 1 cm
h = 3/2 cm

Volume of the rectangular prism = (1/2)(1)(3/2)

Volume of the rectangular prism = (1/2)(1)(3/2) = 0.75 cm³

Volume of the cube = (⅓)³ = 0.037 cm³

Number of cubes that would fill the prism = 0.75/0.037 ≈ 20 cubes.

Learn more about the volume of cube on:

brainly.com/question/1972490

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2 years ago

Write the standard form of the equation of each line given the slope and y-intereept.

Elena-2011 [213]

Answer:

5y + 15x = 25, 9x - y = -4

Step-by-step explanation:

The standard form is Ax + By = C. We can make this simple by first creating the slope intercept equations of both questions:

1. y = (-3/5)x + 5

2. y = 9x + 4

For the first one, we must first get rid of the denominator by multiplying everything by 5, so we get 5y = -15x + 25, and then you can add 3x to both sides to arrive at your first standard eqn, 5y + 15x = 25.

For the second, all you need to do is swap the y and the 4, subtracting both y and 4 from each side, arriving at 9x - y = -4

6 0

3 years ago

A jeweler wants to make 14 grams of an alloy that is precisely 75% gold.. The jeweler has alloys that are 25% gold, 50% gold, &a

Goryan [66]

Given that the jeweler has alloys that are 25% gold, 50% gold, and 82% gold.

As he wants to make 14 grams of an alloy by adding two different alloys that is precisely 75% gold, so one alloy must have a percentage of gold more than 75%.

One alloy is 82% gold and, the second can be chosen between 25% gold, 50% gold, so there are two cases.

Case 1: 82% gold + 50% gold

Let x grams of 82% gold and y grams of 50% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 50% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times y \\\\$

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 50/100 \times (14-x)$ [as x+y=14]

$\Rightarrow 75 \times 14 = 82 \times x + 50 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 50 \times14-50\times x \\\\\Rightarrow 75 \times 14 = 32 \times x + 50 \times14 \\\\\Rightarrow 32 \times x =75 \times 14 - 50 \times14 \\\\$

$\Rightarrow x =(25 \times 14)/32=10.9375$ grams

and $y = 14-x= 14-10.9375=3.0625$ grams.

Hence, 10.9375 grams of 82% gold and 3.0625 grams of 50% gold added to make 14 grams of 75% gold.

Case 2: 82% gold + 25% gold

Let x grams of 82% gold and y grams of 25% gold added to make x+y=14 grams of 75% gold, so

75% of 14 = 82% of x + 25% of y

$\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times y \\\\\Rightarrow 75/100 \times 14 = 82/100 \times x + 25/100 \times (14-x) \\\\ \Rightarrow 75 \times 14 = 82 \times x + 25 \times (14-x) \\\\\Rightarrow 75 \times 14 = 82 \times x + 25 \times14-25\times x \\\\\Rightarrow 75 \times 14 = 57 \times x + 25 \times14 \\\\\Rightarrow 57 \times x =75 \times 14 - 25 \times14 \\\\$