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lakkis [162]
3 years ago
5

Is it (x+1)^2 ? Please help

Mathematics
1 answer:
Leya [2.2K]3 years ago
3 0

Answer:yes you are right

Step-by-step explanation:

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Find the perimeter of the image below
Naily [24]

Answer:

46

Step-by-step explanation:

7 0
3 years ago
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Can you please help me!!!! thank you
vladimir2022 [97]

Answer:

V = J = 92

Step-by-step explanation:

The angles are the same on both shapes.

3 0
3 years ago
The line 3x+4y=24 cuts the x axis at point A and y axis at point B<br><br> Find the lenght if AB
sweet [91]
Length A is (8,0) and the length of B is (0,6)
4 0
3 years ago
A spacecraft is traveling with a velocity of v0x = 5320 m/s along the +x direction. Two engines are turned on for a time of 739
OlgaM077 [116]

Answer:

The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction

Step-by-step explanation:

  1. For a constant acceleration: v_{f}=v_{0}+at, where  v_{f} is the final velocity in a direction after the acceleration is applied, v_{0} is the initial velocity in that direction  before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied.
  2. <em>Then for the x direction</em> it is known that the initial velocity is v_{0x} = 5320 m/s, the acceleration (the applied by the engine) in x direction is a_{x} 1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the  is 739 s. Then: v_{fx}=v_{0x}+a_{x}t=5320\frac{m}{s} +1.79\frac{m}{s^{2} }*739s=6642.81\frac{m}{s}
  3. In the same fashion, <em>for the y direction</em>, the initial velocity is  v_{0y} = 0 m/s, the acceleration in y direction is a_{y} 7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: v_{fy}=v_{0y}+a_{y}t=0\frac{m}{s} +7.18\frac{m}{s^{2} }*739s=5306.02\frac{m}{s}
8 0
3 years ago
Which expressions can be used to compute the approximate area of triangle XYZ? Check all that apply.
lesantik [10]

Given:

In the given ΔXYZ,

Base = 22

Height = 23.1

Also,

Base = 31.9

Height = 15.9

To find the area of the given ΔXYZ.

Formula

The area of a triangle is

A = \frac{1}{2} bh

where, b be the base and

h be the height.

Now,

Taking, b = 22 and h = 23.1 we get,

A = \frac{1}{2} (22)(23.1) sq unit

Again,

Taking,

b = 31.9 and h = 15.9 we get,

A = \frac{1}{2} (31.9)(15.9) sq unit

Therefore,

We can find the approximate area of the triangle by following two expression

a) \frac{1}{2} (22)(23.1) and

b) \frac{1}{2} (31.9)(15.9)

8 0
3 years ago
Read 2 more answers
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