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4 years ago

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When you’re driving a golf ball, a good "follow-through" helps to increase the distance of the drive. A good follow-through mean

s that the club head is kept in contact with the ball as long as possible. Using the impulse-momentum theorem, explain why this technique allows you to hit the ball farther.

1 answer:

Natali [406]4 years ago

3 0

Answer:

$v_{f}$ = F Δt / m

Explanation:

The impulse theorem and momentum is

I = Δp

F Δt = m $v_{f}$ - m v₀

Before touching the ball is without movement, the force is represented by the kinetic energy of the club when it reaches the bottom of the path, so if this force is constant, the time [or the duration of the blow is directly proportional to the speed that the ball acquires.

$v_{f}$ = F Δt / m

The higher this speed, the greater the distance traveled.

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To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the d

frez [133]

The question is incomplete. Here is the complete question.

To understand the decibel scale. The decibel scale is a logarithmic scale for measuring the sound intensity level. Because the decibel scale is logarithmic, it changes by an additive constant when the intensity when the intensity as measured in W/m² changes by a multiplicative factor. The number of decibels increase by 10 for a factor of 10 increase in intensity. The general formula for the sound intensity level, in decibels, corresponding to intensity I is

$\beta=10log(\frac{I}{I_{0}} )dB$ ,

where $I_{0}$ is a reference intensity. for sound waves, $I_{0}$ is taken to be $10^{-12} W/m^{2}$ . Note that log refers to the logarithm to the base 10.

Part A: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 10 times the reference intensity, i.e. $I=10I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part B: What is the sound intensity level β, in decibels, of a sound wave whose intensity is 100 times the reference intensity, i.e. $I=100I_{0}$ ? Express the sound intensity numerically to the nearest integer.

Part C: Calculate the change in decibels ( $\Delta \beta_{2},\Delta \beta_{4}$ and $\Delta \beta_{8}$ ) corresponding to f = 2, f = 4 and f = 8. Give your answer, separated by commas, to the nearest integer -- this will give an accuracy of 20%, which is good enough for sound.

Answer and Explanation: Using the formula for sound intensity level:

A) $I=10I_{0}$

$\beta=10log(\frac{10I_{0}}{I_{0}} )$

$\beta=10log(10 )$

β = 10

<u>The sound Intensity level with intensity 10x is </u><u>10dB</u>.

B) $I=100I_{0}$

$\beta=10log(\frac{100I_{0}}{I_{0}} )$

$\beta=10log(100)$

β = 20

<u>With intensity 100x, level is </u><u>20dB</u>.

C) To calculate the change, take the f to be the factor of increase:

For $\Delta \beta_{2}$ :

$I=2I_{0}$

$\beta=10log(\frac{2I_{0}}{I_{0}} )$

$\beta=10log(2)$

β = 3

For $\Delta \beta_{4}$ :

$I=4I_{0}$

$\beta=10log(\frac{4I_{0}}{I_{0}} )$

$\beta=10log(4)$

β = 6

For $\Delta \beta_{8}$ :

$I=8I_{0}$

$\beta=10log(\frac{8I_{0}}{I_{0}} )$

β = 9

Change is

$\Delta \beta_{2},\Delta \beta_{4}$ , $\Delta \beta_{8}$ = 3,6,9 dB

6 0

3 years ago

PLEASE HELP ASAP!!! THANKS!<br><br> how do stars and planets effect eachother?

Serhud [2]

Answer:

"Planets May Affect the Chemistry of Their Stars. Planets are, by and large, at the mercy of their stars. Not only do stars provide a ready energy source of radiated light and heat, but the mass and gravitational pull of stars flat-out dwarfs the summed masses and pulls of any orbiting companions."

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3 years ago

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g HW 5.6.The Moon and the Earth both orbit the center of mass of the Earth-Moon system.Earth is 81 times more massive than the M

Law Incorporation [45]

Answer:

$R_{cm}$ = 4.688 106 m

Explanation:

The expression for the center of mass is

R cm = 1 / M ∑ $r_{i}$ $m_{i}$

Where M is the total mass of the system, ri and m1 are the distance and mass of each particle from a defined origin

Let's look for the total mass, the mass of the moon is m and that of the earth Me

M = $M_{e}$ + m

M = 81m + m

M = 82 m

The distance from the earth to the moon is R = 384.4 106 m

$R_{cm}$ = 1 / M (M R1 + m R)

$R_{cm}$ = 1 / 82m (0 + m R)

$R_{cm}$ = R / 82

$R_{cm}$ = 384.4 106/82

$R_{cm}$ = 4.688 106 m

The radius of the earth is

$R_{e}$ = 6371 103 m

$R_{e}$ = 6.371 106 m

We can see that the center of mass of the system is within the beating radius

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3 years ago

Which are examples of convection currents ? Select three options.

Veseljchak [2.6K]

<u>Answer</u>:

(B) A pot being heated by an electric burner

(D) A radiator that emits warm air and draws in cool air

(E) A hot air balloon rising and falling in the atmosphere

These are some of the examples of the convection currents.

<u>Explanation</u>:

Earlier, electrons were believed to have positive charges and then electric current were discovered. But later after the invention of electric current and current which is termed to be the flow of electrons and is usually flows from negative to positive terminal. But its convention is not discarded in which current moves from positive terminal to negative and it is called convention current. The direction of current shown in the circuit is said to be the convention current.

Hence, the following are the examples of convention current.

1. Boiling water - The energy travels into the pot from the burner, boiling down the water. Then this warm water is accumulating on the top and colder one is heading down to absorb it, triggering a circular motion.

2. Radiator - Place hot air at the peak and pull cool air at the bottom.

3. Hot air balloon - The air is warmed up by a heating element within the balloon, so the air jumps upwards. This induces the balloon to increase in size due to the inside trapping of the warm air. He removes a few of the warm air when the pilot commences to dive, and cold air takes place, enabling the parachute to drop.

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3 years ago

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Calculate the following forces for a box with a mass=20.0 kg sitting on an incline of 29.0 degrees and a coefficient of friction

Anna007 [38]

Vertical force on the box=mg
<span>the component of gravity parallel=mg*SinTheta </span>
<span>the component of gravity normal=mg*CosTheta </span>
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4 years ago