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choli [55]
3 years ago
14

g HW 5.6.The Moon and the Earth both orbit the center of mass of the Earth-Moon system.Earth is 81 times more massive than the M

oon. Assume that the distance between the centerof the Earth and the Moon is 384,400.0 km. Determine the distance of the center of mass of theEarth-Moon system from the center of the Earth. Does it lie inside or outside the Earth with theradius of 6,371.0 km
Physics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

R_{cm}  = 4.688 106 m

Explanation:

The expression for the center of mass is

       R cm = 1 / M ∑ r_{i} m_{i}

Where M is the total mass of the system, ri and m1 are the distance and mass of each particle from a defined origin

Let's look for the total mass, the mass of the moon is m and that of the earth Me

    M = M_{e} + m

    M = 81m + m

    M = 82 m

The distance from the earth to the moon is R = 384.4 106 m

    R_{cm} = 1 / M (M R1 + m R)

   R_{cm}  = 1 / 82m (0 + m R)

    R_{cm}  = R / 82

   R_{cm}  = 384.4 106/82

   R_{cm}  = 4.688 106 m

The radius of the earth is

    R_{e} = 6371 103 m

    R_{e}  = 6.371 106 m

We can see that the center of mass of the system is within the beating radius

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Answer:

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Explanation:

For this problem we must solve it in parts, let's start by looking for the speed of the two cars after the collision

In the exercise they indicate the weight of each car

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          W_b = 1125 lb

Car B's velocity from v_b = 42.0 mph westward, car A travels east

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             W = mg

             m = W / g

             mₐ = Wₐ / g

             m_b = W_b / g

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Let's reduce to the english system

             v_b = 42.0 mph (5280 foot / 1 mile) (1h / 3600s) = 61.6 ft / s

We define a system formed by the two vehicles, so that the forces during the crash have been internal and the moment is preserved

we assume the direction to the east (right) positive

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           p₀ = mₐ v₀ₐ - m_b v_{ob}

final instant. Right after the crash

           p_f = (mₐ + m_b) v

the moment is preserved

           p₀ = p_f

           mₐ v₀ₐ - m_b v_{ob} = (mₐ + m_b) v

           v = \frac{ m_a \ v_{oa} - m_b \ v_{ob}  }{ m_a +m_b}

we substitute the values

           v = \frac{ 46.875}{82.03} \ v_{oa} -  \frac{35.156}{82.03} \ 61.6

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the total mass is

              M = mₐ + m_b

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              K₀ = ½ M v²

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The work is

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Axis y

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            v² = 2 μ g x  

            v = \sqrt{ 2 \ 0.750 \ 32 \ 17.5}Ra (2 0.750 32 17.5  

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