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2 years ago

10

Which statements are true for the functions g(x) = x2 and h(x) = –x2 ? Check all that apply.

1 answer:

rusak2 [61]2 years ago

8 0

Answer: For any value of x, g(x) will always be greater than h(x).

Step-by-step explanation:all positive numbers are greater than negative numbers

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When x=12, y=8. Find x when y=12

Digiron [165]

<span>x : y is equal to 12 : 8. These can be reduced or cancelled down to 3 : 2 in the same proportions. Therefore, when y is 12, you have to multiply the smallest value y can be by 6, and must do the same to the smallest x value to retain the proportions. x = 18 when y = 12.</span>

6 0

2 years ago

Which description is true about pre-image ABC and image A′B′C′ ?

scoray [572]

Answer:

Option (C)

Step-by-step explanation:

From the graph attached,

In ΔABC and ΔA'B'C',

∠A ≅ ∠A'

∠B ≅ ∠B'

Therefore, ΔABC ~ ΔA'B'C'

Corresponding sides of these triangles will be proportional.

$\frac{\text{AB}}{\text{A'B'}}=\frac{\text{BC}}{\text{B'C'}}=\frac{\text{AC}}{\text{A'C'}}=\frac{2}{6}$

Therefore, ratio of the sides, AC : A'C' = 1 : 3 shows that image triangle A'B'C' is a dilated form of pre-image ABC with a scale factor of 3.

Option (C) will be the correct option.

7 0

3 years ago

One chicken is injected with a growth hormone while another chicken isn't. both chickens are wighed after a year

Margarita [4]

Answer:

weight

Step-by-step explanation:

The weight depends on the chicken

3 0

3 years ago

Triangle DNO has vertices at D(5, 8), N(– 3, 10), and O(– 3, 6). If vertex D is translated 4 units to the right, the best name f

prisoha [69]

Using distance between two points to find the lengths of the edges of the triangle, the correct option is:

b. Isosceles

The distance between two points, $(x_1,y_1)$ and $(x_2,y_2)$ , is given by:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Vertex D is translated 4 units to the right is (9,8).

The lengths of the edges are:

$DN = \sqrt{(9 - (-3))^2 + (8 - 10)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$DO = \sqrt{(9 - (-3))^2 + (8 - 6)^2} = \sqrt{12^2 + 2^2} = \sqrt{148}$

$NO = \sqrt{(-3 - (-3))^2 + (10 - 6)^2} = \sqrt{0^2 + 4^2} = 4$

<u>Two edges of the same length</u>, hence, it is an isosceles triangle, given by option b.

You can learn more about distance between two points at brainly.com/question/18345417

6 0

2 years ago

The product of x and the sum of 6 and 8 times the square of x

Kamila [148]

Let's separate this problem into several parts:

1. The product of x

AND

2. The sum of 6 and 8

TIMES

3. The square of x

So translating this word problem into numbers, we have:

x TIMES (6+8) TIMES x²

so that is:

x * 14 * x²

which is:

14x^(2+1) = 14x³

8 0

3 years ago

Read 2 more answers