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2 years ago

On a map 1 inch = 50 miles. If two cities are 3 1/2 inches apart, how many miles are they apart?

1 answer:

3 0

I think 175 miles.
Since 1 = 50 miles and the cities are 3 1/2 miles apart, all you need to do is multiply 50 x 3 which is 150. Then you need to solve the 1/2, which 1/2 of 50 is 25. 150+25 is 175. So the answer is 175 miles.

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Molly measured the diameter of her bike tire and found that it was 2 feet across. She estimated that for every turn of the tire,

natulia [17]

Answer:

Molly's estimation was approximately correct.

Step-by-step explanation:

Given:

Diameter of bike tire = 2 feet

Also Given:

She estimated that for every turn of the tire, the bike traveled about 6 feet.

Estimated Distance traveled = 6 feet

We need to find that whether her estimation reasonable.

Solution:

Now we know that Distance traveled is equal to Circumference of tire.

Since Tire is in circular shape.

We can say that;

Circumference of the tire will be π times diameter.

framing in equation form we get;

Circumference of the tire = $\pi \times 2 = 6.28 \ feet$

Now The actual distance traveled is 6.28 feet and Molly estimated as 6 feet.

Hence we can say that Molly's estimation was approximately correct.

5 0

3 years ago

ANSWER IT CORRECTLY FOR BRAINLIEST Amelia built a scale model of a float, using the scale 48:7. The measurements of the actual f

Rashid [163]

Answer:

The third one :)

Step-by-step explanation:

6 0

2 years ago

The left and right page numbers of an open book are consecutive integers whose sum is 53. Find these page numbers.

Mice21 [21]

26 left 27 right. If you add them together, you get a sum of 53

4 0

3 years ago

An isosceles trapezoid has base angles 45 and bases of lengths 9 and 15 the area pf the trapezoid is

Nadusha1986 [10]

Tangent 45 = height / 3
height = 3 * tan (45)
height = 3 * 1
height = 3

Trapezoid area = ((sum of the bases) ÷ 2) • height

Trapezoid area = (9 + 15) /2 * height

Trapezoid area = 12 * 3

Trapezoid area = 36

7 0

3 years ago

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago