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Leona [35]
3 years ago
5

Which statement is true about the domain of y = 3(2^-x)? Explain.

Mathematics
1 answer:
SVEN [57.7K]3 years ago
8 0
We want to determine the domain of {y=3 \cdot 2^{-x}=3 \cdot ({2^{-1}})^x=3 \cdot ({ \frac{1}{2}})^x

any function of the form y=f(x)=a \cdot b^x is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.

The domain of such functions is all real numbers.

That is for any x, the expression <span>3(2^-x) "makes sense".



Answer: </span><span>The domain is all real numbers</span>
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anastassius [24]

Answer:

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6 0
3 years ago
Compare partial products and regrouping
Stella [2.4K]

Let us first describe how partial product and regrouping are alike:

Partial Products and Regrouping are alike because both methods are multiplied by one number and if the product of the number has 2 digits it can be carried.

Now let us discuss how they are different:

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5 0
3 years ago
NEED HELP ASAP PLEASE IM TRYNA PASS
V125BC [204]

Answer:

segment SV

Step-by-step explanation:

Observing the figure

we know that

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3 years ago
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mr Goodwill [35]

Answer:

(-1,0)

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Define two terms, each containing the variables x and y, with exponents on each. (For example: 10x3y−5.) Find the quotient of th
Serjik [45]

Answer:Two such terms are 7x^3*y^9 and -3x*y^5

Their quotient is

7x^3*y^9

--------------

-3x*y^5

This can be simplified as follows:

The numerical coefficients become -7/3.

x^3/x = x^3*x^1 = x^(3 - 1) = x^2 (we subtract the exponent of x in the denominator from the exponent of x in the numerator).

Next, y^9*y^5 = y^4.

The quotient in final reduced form is then (-7/3)x^2*y^4

7 0
3 years ago
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