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4 years ago

Convert the improper fraction to a mixed number. negative StartFraction 28 Over 3 EndFraction

1 answer:

8 0

How many times does 3 go into 28? let's see 28÷3 is 9.333 so...9 whole times, thus 9 * 3 is 27 so

$\bf \cfrac{28}{3}\implies \cfrac{27+1}{3}\implies \cfrac{27}{3}+\cfrac{1}{3}\implies 9+\cfrac{1}{3}\implies 9\frac{1}{3}$

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Curved surface area of half cylinder

cricket20 [7]

Answer:

curved surface area of half cylinder is

Step-by-step explanation:

πr2h

3 0

3 years ago

Read 2 more answers

There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b

WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

a>b>c

$a>b>c>d\\\implies x$

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together $=O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)$

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) $\frac{c}{3}$

Using (1)

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}$

Similarly

$\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}$

So,

$\frac{c}{3}$

3 0

3 years ago

How do you find 0.11111-K=0.01121

Doss [256]

I believe that the answer to this is k=0.0999

4 0

4 years ago

Use the diagram to solve for the three variables so that the quadrilateral will be a rhombus. Show all of your work for full cre

satela [25.4K]

Answer:

x = 4
y = 4
z = 7

Step-by-step explanation:

Each triangle is a right triangle, and all are congruent. So ...

90 -m∠CAB = (1/2)m∠CDA

90 -(4x +33) = (1/2)(12x +34)

57 -4x = 6x +17 . . . . . . . eliminate parentheses

40 = 10x . . . . . . . . . . . . .add 4x-17

4 = x

We also have ...

2m∠CAD = m∠BCD

2(3z +28) = 10z +28

6z +56 = 10z +28 . . . . . eliminate parentheses

28 = 4z . . . . . . . . . . . . . .subtract 6z+28

7 = z . . . . . . . . . . . . . . . . divide by 4

Since BC = CD ...

x = y = 4

The values of the three variables are ...

x = 4, y = 4, z = 7.

3 0

3 years ago

Help please.........

Crazy boy [7]

Answer:

Step-by-step explanation:

I did the test and got it right

8 0

4 years ago