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Trava [24]
3 years ago
11

Write the equation of a line that contains the points 4,1 and -4,5

Mathematics
1 answer:
Bingel [31]3 years ago
6 0

Answer:   y = -1/2x+3

Step-by-step explanation:

Since we are given two points on the graph, we are going to use these points to find the slope using the formula m = y2-y1 / x2-y1, where m is equal to the slope.

Since it doesn't matter which points are 1 and which are two, we are just going to make (-4,5) x2 and y2, and (4,1) x1 and y1. Plugging everything in we get 5-1/-4-4 = 4/-8 = -1/2. So, -1/2 is our slope.

Now we can plug in the slope and one of our previous points, again it doesn't matter which one, into y = mx + b to find b, the y-intercept. We are going to use the point (4,1) and when we plug it in we get 1 = -1/2(4) + b and b ends up being equal to 3.

So when we plug in 3 for the y - intercept and  -1/2 for the slope, we get y = -1/2x+3

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What is the solution to the following system of equations? 4x + 2y = 18 x − y = 3
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For this case we have the following system of equations:

4x + 2y = 18\\x-y = 3

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x = 3 + y

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We look for the value of the variable "x":

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Answer:

(x, y) :( 4,1)

Option D

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