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Trava [24]
3 years ago
11

Write the equation of a line that contains the points 4,1 and -4,5

Mathematics
1 answer:
Bingel [31]3 years ago
6 0

Answer:   y = -1/2x+3

Step-by-step explanation:

Since we are given two points on the graph, we are going to use these points to find the slope using the formula m = y2-y1 / x2-y1, where m is equal to the slope.

Since it doesn't matter which points are 1 and which are two, we are just going to make (-4,5) x2 and y2, and (4,1) x1 and y1. Plugging everything in we get 5-1/-4-4 = 4/-8 = -1/2. So, -1/2 is our slope.

Now we can plug in the slope and one of our previous points, again it doesn't matter which one, into y = mx + b to find b, the y-intercept. We are going to use the point (4,1) and when we plug it in we get 1 = -1/2(4) + b and b ends up being equal to 3.

So when we plug in 3 for the y - intercept and  -1/2 for the slope, we get y = -1/2x+3

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Line Equation from Two Points
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Hi!

We can use <u>point-slope form </u>to solve this.

y-y_{1} =m(x -x_{1})

y_{1}<em> and </em>x_{1}<em> will be from one of the points.</em>

<u>First, we have to find </u>m<u>, the slope. We can use the slope equation to get this.</u>

\frac{y_{1} -y_{2} }{x_{1} -x_{2} }

<em>Plug in your points:</em>

\frac{4-0}{8-(-8)} =\frac{4-0}{8+8} =\frac{4}{16} =\frac{1}{4}

Your slope is \frac{1}{4}

<u><em>Now plug points and slope into point-slope equation. We will use (8, 4).</em></u>

y-4=\frac{1}{4} (x-8)

Now, if you want to get it into y = mx + b form, you have to solve for y:

y-4=\frac{1}{4} (x-8)

y-4=\frac{1}{4} x-2

y=\frac{1}{4} +2

Your equation is y=\frac{1}{4} +2

<u><em>For more information on how to get the equation of a line when given two points, see here:</em></u>

brainly.com/question/986503

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