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3 years ago

Write the equation of a line that contains the points 4,1 and -4,5

Mathematics

1 answer:

Bingel [31]3 years ago

6 0

Answer: y = -1/2x+3

Step-by-step explanation:

Since we are given two points on the graph, we are going to use these points to find the slope using the formula m = y2-y1 / x2-y1, where m is equal to the slope.

Since it doesn't matter which points are 1 and which are two, we are just going to make (-4,5) x2 and y2, and (4,1) x1 and y1. Plugging everything in we get 5-1/-4-4 = 4/-8 = -1/2. So, -1/2 is our slope.

Now we can plug in the slope and one of our previous points, again it doesn't matter which one, into y = mx + b to find b, the y-intercept. We are going to use the point (4,1) and when we plug it in we get 1 = -1/2(4) + b and b ends up being equal to 3.

So when we plug in 3 for the y - intercept and -1/2 for the slope, we get y = -1/2x+3

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2 years ago

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2 years ago

Line Equation from Two Points

Verdich [7]

Hi!

We can use point-slope form to solve this.

$y-y_{1} =m(x -x_{1})$

$y_{1}$ and $x_{1}$ will be from one of the points.

First, we have to find $m$ , the slope. We can use the slope equation to get this.

$\frac{y_{1} -y_{2} }{x_{1} -x_{2} }$

Plug in your points:

$\frac{4-0}{8-(-8)} =\frac{4-0}{8+8} =\frac{4}{16} =\frac{1}{4}$

Your slope is $\frac{1}{4}$

Now plug points and slope into point-slope equation. We will use (8, 4).

$y-4=\frac{1}{4} (x-8)$

Now, if you want to get it into y = mx + b form, you have to solve for y:

$y-4=\frac{1}{4} (x-8)$

$y-4=\frac{1}{4} x-2$

$y=\frac{1}{4} +2$

Your equation is $y=\frac{1}{4} +2$

For more information on how to get the equation of a line when given two points, see here:

brainly.com/question/986503

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2 years ago

Why is it important to consider scale when graphing inequalities?

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