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Troyanec [42]
3 years ago
11

IF U ANSWER MY QUESTION, ILL HELP YOU ANSWER YOURS. PLZ PLZ PLZ PLZ ANSWER THE QUESTION!!!!!!!!!

Mathematics
1 answer:
ratelena [41]3 years ago
4 0

Given : The Distance between Rotherham and London is 156 Miles

Given : Kim drives at a Speed of 60 Miles per Hour

It means : Kim travels 60 Miles in One Hour

\mathsf{\implies Kim\;travels\;156\;Miles\;in : (\frac{156}{60})\;Hours}

\mathsf{\implies Kim\;travels\;156\;Miles\;in\;2.6\;Hours}

\mathsf{\implies Kim\;travels\;156\;Miles\;in\;2\;Hours\;36\;Minutes}

⇒ Kim does not Arrive London before 10:00

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Consider the vectors u <-4,7> and v= <11,-6>
coldgirl [10]

Answer:

u + v = <7 , 1>

║u + v║ ≅ 7

Step-by-step explanation:

* Lets explain how to solve the problem

- We can add two vector by adding their parts

∵ The vector u is <-4 , 7>

∵ The vector v is <11, -6>

∴ The sum of u and v = <-4 , 7> + <11 , -6>

∴ u + v = <-4 + 11 , 7 + -6> = <7 , 1>

∴ The sum u and v is <7 , 1>

* u + v = <7 , 1>

- The magnitude of the resultant vector = √(x² + y²)

∵ x = 7 and y = 1

∵ ║u + v║ means the magnitude of the sum

∴ The magnitude of the resultant vector = √(7² + 1²)

∴ The magnitude of the resultant vector = √(49 + 1) = √50

∴ The magnitude of the resultant vector = √50 = 7.071

* ║u + v║ ≅ 7

4 0
4 years ago
Pls help due in 10 mins
BabaBlast [244]

Answer:

Try inserting the Problem

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
HELP PLEASE BOTH QUESTIONS <br> ILL MARK BRAINLIST
pychu [463]

Answer:

Sorry but all I know is number 7 is x=3 I dont know how to explain

3 0
3 years ago
Two lines, C and D, are represented by the following equations:
Usimov [2.4K]
The second choice is the answer
5 0
4 years ago
A rectangle is 6yards longer than it is wide. Find the dimensions of the rectangle if it’s area is 187 square yards
emmasim [6.3K]

Answer:

Width = 11 yards

Length = 17 yards

Step-by-step explanation:

First of all, the length of the rectangle is 6 yards longer than the width, this means, length = width + 6 yards. This dimensions can be represented on figure 1, where <em>w</em> is width, and <em>l</em>, for length.

We know the area of a rectangle is A = width x length

For our case 187 = w . (w + 6)

Using the Distributive Property for the multiplication we obtain

187 = w^{2} +6w

w^{2} +6w-187 =0,

Using the quadratic formula w=\frac{-b\±\sqrt{b^{2}-4ac } }{2a} where a = 1, b = 6, c = - 187 and replacing into the formula, we will have:

w=\frac{-6\±\sqrt{6^2-4(1)(-187)} }{2(1)}

w=\frac{-6\±\sqrt{36+748} }{2}=\frac{-6\±\sqrt{784} }{2}=\frac{-6\±28}{2}

We have two options: w=\frac{-6+28}{2}=\frac{22}{2}=11  yards

Or

w=\frac{-6-28}{2}=\frac{-34}{2}=-17 yards But a distance (width) can not be negative so, this answer for w must be discarded.

The answer must be width = 11 yards.

To find the length l =\frac{187}{11}=17 yards

6 0
3 years ago
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