Iron (II) iodide solution will contain the highest concentration of iodide ions. Option D is the right answer.
Explanation:
Reference table F is used to check the solubility of the metal compounds formed. It tells if the compound is soluble or insoluble in water.
From the table, it is seen that Mercury, silver and lead form insoluble complex with iodide ions. This means that they have low concentration of dissolved iodide ions. These three metals lead, silver and mercury are given as exception in the table F.
Thus iron(II) iodide will have highest concentration of iodide ions when dissolved in water.
It's wood i believe. (dont mind this i had to make it longer)
Molarity is moles over liter. When checking for molarity, before diving, make sure the units are correct. In this case, both units are moles and liters, so we can assume the molarity is 3/12, or 0.25 M
Answer:
T½ = 16hours
Explanation:
Final mass (N) = 10g
Initial mass (No) = 20g
Time (t) = 16hours
T½ = ?
T½ = In2 / λ
But λ = ?
In(N/No) = -λt
In(10/20) = -(λ * 16)
In(0.5) = -16λ
-0.693 = -16λ
λ = 0.693 / 16
λ = 0.0433
Note : λ is known as the disintegration constant
T½ = In2 / λ
T½ = 0.693 / 0.0433
T½ = 16hours
The half-life of the sample is 16hours
