Answer: 0.2
Step-by-step explanation:
Let
denote the value on the
-th drawn ball. We want to find the expectation of
, which by linearity of expectation is
![E[S]=E\left[\displaystyle\sum_{i=1}^5B_i\right]=\sum_{i=1}^5E[B_i]](https://tex.z-dn.net/?f=E%5BS%5D%3DE%5Cleft%5B%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E5B_i%5Cright%5D%3D%5Csum_%7Bi%3D1%7D%5E5E%5BB_i%5D)
(which is true regardless of whether the
are independent!)
At any point, the value on any drawn ball is uniformly distributed between the integers from 1 to 10, so that each value has a 1/10 probability of getting drawn, i.e.

and so
![E[X_i]=\displaystyle\sum_{i=1}^{10}x\,P(X_i=x)=\frac1{10}\frac{10(10+1)}2=5.5](https://tex.z-dn.net/?f=E%5BX_i%5D%3D%5Cdisplaystyle%5Csum_%7Bi%3D1%7D%5E%7B10%7Dx%5C%2CP%28X_i%3Dx%29%3D%5Cfrac1%7B10%7D%5Cfrac%7B10%2810%2B1%29%7D2%3D5.5)
Then the expected value of the total is
![E[S]=5(5.5)=\boxed{27.5}](https://tex.z-dn.net/?f=E%5BS%5D%3D5%285.5%29%3D%5Cboxed%7B27.5%7D)
a) The cost for 10 mile taxi ride is $18
b) The cost for m mile taxi ride is 1.5 m + 3
Step-by-step explanation:
Step 1 :
The fixed charges for the pick up = $3
Charges per mile = $1.50
Let s denote the total miles driven and t be the total cost for the trip
This can be represented by the equation
t = 3 + 1.5s
Step 2:
Distance traveled by Jonathan in his trip = 10 miles
So cost for riding 10 miles is
t = 3 + 1.5(10) = 3 + 15 = $18
The cost for 10 mile taxi ride is $18
Step 3 :
If the distance traveled is m miles, then substituting s = m in the above equation we get the cost as 1.5 m + 3
Step 4 :
Answer :
a) The cost for 10 mile taxi ride is $18
b) The cost for m mile taxi ride is 1.5 m + 3
given: 
$\therefore Ac=\frac{(2)2}{2}=2$