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zepelin [54]
3 years ago
11

There are 20 sixth graders and 25 seventh graders. If each group has the greatest possible number of club members, how many grou

ps of sixth graders and how many groups of seventh graders will there be? use numbers and words to explain your answer.
Mathematics
1 answer:
seraphim [82]3 years ago
6 0
4(5)=20
5(5)=25
4 groups of 6th grader
5 groups of 7th graders
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75 is the product of Greg’s height and 5
KatRina [158]

Answer:

Let Greg's height be = x

According to the question;

=  > x \times 5 = 75 \\  \\  =  > x =  \frac{75}{5}  \\  \\  =  > x = 15

So, Greg's height (x) = 15 years

7 0
3 years ago
Read 2 more answers
Julio ​says, "If you subtract 13 from my number and multiply the difference by -3​, the result is -54 ​." What is Julios​'s ​num
Alchen [17]

Answer:Julios​'s ​number is 31

suppose: Julios​'s ​number is x

because Julio ​says, "If you subtract 13 from my number and multiply the difference by -3​, the result is -54 ​"

=> we have: (x - 13).(-3) = -54

                 <=>  x  - 13 = (-54):(-3) = 18

                   <=> x = 18 + 13 = 31

                   <=> x = 31

Step-by-step explanation:

7 0
3 years ago
Do the side lengths 15,20 and 25 form a right triangle?<br><br><br> PLEASEEEE HELPPPP!!! asap
sveticcg [70]
<h3>Answer: Yes, those sides form a right triangle</h3>

===================================================

Work Shown:

a^2+b^2 = c^2

15^2+20^2 = 25^2

225+400 = 625

625 = 625

Since the last equation is true, this makes the first equation true for those a,b,c values. Therefore, by the pythagorean theorem converse, this is a right triangle.

Side note: c is always the longest side.

6 0
2 years ago
Show your solution follow the steps need an answer, please need an answer, please.​
STatiana [176]

Answer:

Step-by-step explanation:

27 ) 2x² - x - 1 = 0

2x² - 2x +  x  - 1 = 0

2x ( x - 1) + (x - 1) = 0

(x - 1)(2x + 1) = 0

x - 1 = 0  ; 2x + 1 = 0

x = 1   ;     2x = -1

                  x = -1/2

x = 1 ; -1/2

Option b

28) Area of a rectangle = 24 cm²

length * width = 24

(3x +2 )(2x -1) = 24

3x(2x -1) + 2(2x - 1) = 24

3x *2x - 3x *1 + 2*2x - 2*1 = 24

6x² -3x + 4x - 2= 24

6x² + x - 2 -24 = 0

6x² + x - 26 = 0

6x² -12x + 13x - 26 = 0

6x(x - 2) + 13(x - 2) = 0

(x -2)(6x +13) = 0

x = 2      {Ignore 6x + 13 as it gives negative value}

length = 3x + 2 = 3*2 + 2 = 6 + 2 = 8 cm

Width  = 2x - 1 = 2*2 - 1 = 4 - 1 = 3 cm

29) Area of square = 900 cm²

Side² = 900

(5x)² = 900

25x² = 900

x² = 900/25

x² = 36

x = √36 = √6*6

x = 6 cm

30) base = b cm

height = b + 2

Area of triangle =  24 cm²

\dfrac{1}{2}base*height = 24\\\\\dfrac{1}{2}*b*(b+2) = 24\\

b(b + 2) = 24*2

b² + 2b = 48

b² + 2b - 48 = 0

b²  - 6b + 8b  - 48 = 0

b(b - 6) + 8(b - 6) = 0

(b - 6) (b + 8) = 0

b - 6 = 0    {Ignore b +8 = 0 as it gives negative value}

b = 6 cm

height = 6+ 2 = 8 cm

5 0
3 years ago
4x+y=8 and x+3y=8 graphed
IRISSAK [1]
standard \ linear \ equation\ :\\\\y=ax+b\\\\ \begin{cases} 4x+y=8\ \ |\ subtract\ 4x\ to\ both\ sides\\ x+3y=8 \ \ |\ subtract\ x\ to\ both\ sides \end{cases}\\\\\begin{cases} y=-4x+8 \\ 3y=-x+8\ \ | \ divide \ each \ term \ by \ 3 \end{cases}

\begin{cases} y=-4x+8 \\ y=-\frac{1}{3}x+\frac{8}{3} \end{cases}\\\\y=-4x+8\\ To \ find \ the \ x-axis \ intersection \ point, \\set \ y \ equal \ to \ zero \ and \ solve \ for \ x : \\ \\y=0 \ \to 0=-4x+8\\\\4x=8 \ \ | \ divide \ both \ sides\ by\ 4 \\\\x=2\\\\ point : \ \ (2,0)
 
To \ find \ the \ y-axis \ intersection \ point, \\set \ x \ equal \ to \ zero \ and \ solve \ for \ y : \\ \\x=0 \ \to y=-4 \cdot 0+8\\ y=8 \\ point: \ \ (0,8)


y=-\frac{1}{3}x+\frac{8}{3}\\\\ \ the \ x-axis \ intersection \ point \\ \\y=0 \ \to 0=-\frac{1}{3}x+\frac{8}{3}\\ \frac{1}{3}x=\frac{8}{3} \ \ | \ multiply\ both\ sides\ by\ 3 \\\\x=8 \\\\point: \ \ (8,0)

the \ y-axis \ intersection \ point \\ \\x=0 \ \to y=-\frac{1}{3} \cdot 0+\frac{8}{3} \\ y=\frac{8}{3} \\ point : \ \ (0,\frac{8}{3})


Answer :\\\\ \begin{cases} y=-4x+8 \ \ | \ multiply \ each \ term \ by \ (-3) \\ 3y=-x+8 \end{cases}\\\begin{cases} -3y=12x-24 \\ 3y=-x+8 \end{cases}\\+-------\\0=11x-16\\11x=16\ \ | \ divide \ both \ sides\ by\ 11\\x=\frac{16}{11}

y=-4 \cdot \frac{16}{11}+8 \\ y=- \frac{ 64}{11}+\frac{88}{11}\\y= \frac{24}{11}\\\\\begin{cases} x=\frac{16}{11} \\ y=\frac{24}{11} \end{cases}


3 0
3 years ago
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