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ivann1987 [24]
3 years ago
5

Suppose an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron. Comple

te the nuclear chemical equation below so that it describes this nuclear reaction.
____ → 30P15 + 1n0
Chemistry
1 answer:
AfilCa [17]3 years ago
5 0

Explanation:

An alpha particles is basically a helium nucleus and it contains 2 protons and 2 neutrons.  

Symbol of an alpha particle is ^{4}_{2}\alpha. Whereas a neutron is represented by a symbol ^{1}_{0}n, that is, it has zero protons and only 1 neutron.

Therefore, reaction equation when an aluminum- nuclide transforms into a phosphorus- nuclide by absorbing an alpha particle and emitting a neutron is as follows.

        ^{27}_{13}Al + ^{1}_{0}n \rightarrow ^{30}_{15}P + ^{1}_{0}n

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