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3 years ago

What is 92, 48, 46, 52, 57, 58, 52, 61, 56 least to greatest?

Mathematics

2 answers:

Anit [1.1K]3 years ago

4 0

Answer:

46, 48, 52, 52, 56, 57, 58, 61, 92

Step-by-step explanation:

solong [7]3 years ago

3 0

Hi There.

Your answer would be

46, 48, 52, 52, 56, 57, 58, 61, 92

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Need to know angle 1, angle 2, angle 3

wolverine [178]

Answer: Step-by-step explanation:

angle 1=41°

angle 2=angle 1=41°

angle 3=180-2×41=98

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2 years ago

In the number 5.3779, how does the value of 7 in the hundredths place compare to the value of the 7 in the thousandth place?

anygoal [31]

Answer:

(b)

Step-by-step explanation:

The hundredths place is immediately to the left of the thousandths place. In our base-10 number system, moving a digit to the left one place increases its value by a factor of 10.

The value of 7 in the hundredths place is 10 times the value of 7 in the thousandths place.

6 0

2 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

3 years ago

Help please no links or I’ll report

vfiekz [6]

Answer. the answer for the problem you asked is A

8 0

2 years ago

50 POINTS

Naya [18.7K]

Answer:

From the box plot we get:

Minimum - 14
Maximum - 88
Quartile 1 - 34
Quartile 3 - 65
Median - 48

7 0

2 years ago

Read 2 more answers