These 2 equations has no solution and the equations are independent of each other.
<u>Step-by-step explanation:</u>
-10x² -10y² = -300 ----a
5x² + 5y² = 150 ---- b
While trying to solve this,
We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.
10x² + 10y² = 300 ----c
-10x² -10y² = -300 ---a
Everything cutoff, we will get 0, and there is no solution to these equations.
Answer: Required expression = 8h +3.50
Emilia's job pay $ 43.5 in a day when she works 5 hours.
Step-by-step explanation:
Given: Hourly earning = $8.00
gas allowance per day = $3.50
Pay per day = (Hourly earning ) x (Number of hours ) + (gas allowance per day)
Let h = number of hours
Pay per day = 8h +3.50
If Emily worked for 5 hours, then put h= 5, we get
Pay per day = 8(5) +3.50
= $ 40 +3.50
= $ 43.5
Required expression = 8h +3.50
Emilia's job pay $ 43.5 in a day when she works 5 hours.
Given
We have to set the restraint
because a square root is non-negative, and thus it can't equal a negative number. With this in mind, we can square both sides:
The solutions to this equation are 7 and -2. Recalling that we can only accept solutions greater than or equal to -1, 7 is a feasible solution, while -2 is extraneous.
Similarly, we have
So, we have to impose
Squaring both sides, we have
The solutions to this equation are 5 and 10. Since we only accept solutions greater than or equal to 7, 10 is a feasible solution, while 5 is extraneous.
We can represent this situation by the equation 2x+4x+5x=33.
Then 11x=33, and x = 3.
Then the children's ages are in the ratio 2x:4x:5x, or 2(3):4(3):5(3), or
6:12:15.
Do these 3 ages add up to 33? 6 + 12 + 15 = 33? YES!
The children's ages are 6, 12 and 15 years respectively.
Answer:
Step-by-step explanation:
Let x be the number of hours
Rental A charges:
Rate per hour = $4.50
Rate for x hours = 4.50x
Equation: 15 + 4.50x
Rental B charges:
Rate per hour = $ 5
Rate for x hours = 5x
Equation: 12.50 + 5x
