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Sophie [7]
3 years ago
15

A marketing consultant uses the job costing system and has a pre-determined overhead rate of $15 per direct labor hour. This amo

unt is based on an estimated overhead of $30,000 and an average time of 5.0 hours per job. Job #521 incurred direct material costs of $50 and 6 direct labor hours costing of $75 per hour. The total cost of job #521 is_.
A. $155.
B. $215.
C. $565.
D. $590
Business
1 answer:
monitta3 years ago
7 0

Answer:

D. $590

Explanation:

Predetermined overhead rate = $15 per labour hour

Direct Material cost = $50

Labor rate = $75 per hour

Number of Direct labor hour = 6

Direct labor cost = 6 x 75 = $450

Overhead applied cost = Predetermined overhead rate x Direct labor hours

Overhead applied cost = 15 x 6 = $90

Total cost = $50 + $450 + $90

Total cost = $590

So, the correct answer is D. $590

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Which of the following are true?
laiz [17]

Answer:

c. Payback is the amount of time to recover the initial investment. No discounting occurs and all cash flows after the payback period are not accounted for. The rule is intuitive and used by small business owners

Explanation:

Net present value is the present value of after tax cash flows from an investment less the amount invested.  The NPV does account for all cash flows as well as time value of money.

Internal rate of return is the discount rate that equates the after tax cash flows from an investment to the amount invested . The IRR does account for all cash flows.

The discounted payback period discounts cash flows

3 0
3 years ago
This year, Major Healy paid $40,000 of interest on a mortgage on his home (he borrowed $800,000 to buy the residence in 2015; $9
icang [17]

Answer:

$50,000

Explanation:

The computation of the interest expense for deduction is shown below:

= Interest on a mortgage on his home + Interest on a mortgage on his vacation home  

= $40,000 + $10,000

= $50,000

All other information which is given in the question is not relevant for the computation part. Hence, ignored it  

We simply add both types of interest related to a mortgage on the home

5 0
3 years ago
You are interested in valuing a 2-year semi-annual corporate coupon bond using spot rates but there are no liquid strips availab
Scorpion4ik [409]

Answer:

Following are the solution to this question:

Explanation:

Assume that r_1  will be a 12-month for the spot rate:

\to 1.25 \% \times \frac{100}{2} \times 0.99 + \frac{(1.25\% \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{100} \times \frac{100}{2} \times 0.99 + \frac{(\frac{1.25}{100} \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{2} \times 0.99 + \frac{(\frac{1.25}{2} +100)}{(1+\frac{r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 0.625 +100)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 100.625)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\

\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\\to 0.61875 -98 = \frac{402.5}{(2+r_1)^2}\\\\\to -97.38125= \frac{402.5}{(2+r_1)^2}\\\\\to (2+r_1)^2= \frac{402.5}{ -97.38125}\\\\\to (2+r_1)^2= -4.13\\\\ \to r_1=3.304\%

Assume that r_2  will be a 18-month for the spot rate:

\to 1.5\% \times \frac{100}{2} \times 0.99+1.5\%  \times \frac{100}{2} \times \frac{1}{(1+ \frac{3.300\%}{2})^2}+\frac{(1.5\%  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\\to \frac{1.5}{100} \times \frac{100}{2} \times 0.99+\frac{1.5}{100}  \times \frac{100}{2} \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{100}  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\

\to \frac{1.5}{2}  \times 0.99+\frac{1.5}{2}\times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{2} +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 0.7425+0.75 \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(0.75  +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1+0.0165)^2}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1.033)}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\

\to 1.4925 \times 0.96+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328-97= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to -95.5672= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to (1+\frac{r_2}{2})^3= -1.054\\\\\to r_2=3.577\%

Assume that r_3  will be a 18-month for the spot rate:

\to 1.25\% \times \frac{100}{2} \times 0.99+1.25\% \times \frac{100}{2} \times \frac{1}{(1+\frac{3.300\%}{2})^2}+1.25\%\times\frac{100}{2} \times \frac{1}{(1+\frac{3.577\%}{2})^3}+(1.25\% \times \frac{\frac{100}{2}+100}{(1+\frac{r_3}{2})^4})=96\\\\

to solve this we get r_3=3.335\%

4 0
3 years ago
Three years ago, you invested $3,350.00. Today, it is worth $4,100.00. What rate of interest did you earn
Anastasy [175]

Answer:

6.97%

Explanation:

the formula to be used is

The formula for calculating future value:

FV = P (1 + r)^n

FV = Future value  

P = Present value  

R = interest rate  

N = number of years  

$4,100.00 = $3,350.00 x ( 1 + r)^3

divide both sides of the equation by $3,350.00

$4,100.00 / $3,350.00 = ( 1 + r)^3

1.223881 = ( 1 + r)^3

find the cube root of both sides

1.069661 = 1 + r

r = 6.97%

7 0
3 years ago
Which of the following skills is used by active listeners?
s344n2d4d5 [400]
B is the answer to this
6 0
3 years ago
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