Answer:
trapezoid area = ((sum of the bases) ÷ 2) • height
trapezoid area = ((6 + 12) / 2) * height
trapezoid area = 18 / 2 * height
height = 99/9 = 11
Step-by-step explanation:
Answer:
Step-by-step explanation:
![(\frac{5}{2})^{x}+(\frac{5}{2})^{(x+3)}=(\frac{5}{2})^{x}+(\frac{5}{2})^{x}*(\frac{5}{2})^{3}\\\\=(\frac{5}{2})^{x}*[1+(\frac{5}{2})^{3}]](https://tex.z-dn.net/?f=%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B%28x%2B3%29%7D%3D%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2A%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B3%7D%5C%5C%5C%5C%3D%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7Bx%7D%2A%5B1%2B%28%5Cfrac%7B5%7D%7B2%7D%29%5E%7B3%7D%5D)
Therefore,
First of all, let's consider the line, since it's simpler to graph: we draw the endpoints and connect them:
So, you just need to draw the points
As for the trigonometric function, we have to start from the parent function 
and derive the graph of its child function via transformations:
- When we multiply the whole function by 2, we stretch the graph vertically. So, the function has still period
, but now it ranges from -2 to 2 instead of from -1 to 1 (amplitude 2) - When we multiply the argument by 2, we compress the function horizontally. So, the new period becomes
, and the function makes two complete oscillations from 0 to
You can see the two functions in the image below. You can also see that the two graphs cross 4 times, meaning that the equation
has four solutions.
When we multiply our servings by a given amount, we're not multiplying our cost of cake by the same amount. This tells us that this is not proportional. One way to think about proportional relationships, we already said, that the ratio between the variables will be equivalent.
If all things can be made at the same time, then it would look something like this(all numbers should be rounded down):
127 of Prep: Wreath:127/3 = 42 prepped
127 of Prep: Tree:127/14 = 9 prepped
127 of Prep: Sleigh:127/4 = 31 prepped
104 of Painting: Wreath:104/2 = 52 painted(but because only 42 were prepped, your number will be 42 still)
104 of Painting: Tree:104/3 = 34 painted(As stated above, but with only 9)
104 of Painting: Sleigh:104/17 = 6 painted(this number will overwrite the number of prepped sleighs as only 9 could be painted in the allotted time.)
133 of Firing: Wreath:133/9 = 14 ready to go
133 of Firing: Tree:133/4 = 33(but only nine were painted so the number ready to go is 9)
133 of Firing: Sleigh:133/7 = 19(but only 6 are ready to go)
Final Results: Wreath - 14
Tree - 9
Sleigh - 6
