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FrozenT [24]
4 years ago
6

C) A line through (4, 12) and (7,3). ANSWER:​

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
6 0

Answer: y=-9/4x+21

Step-by-step explanation:

To find a line that passes through the given points, we can use them to find the slope. Once we have the slope, we can plug in any point and solve for the y-intercept. The formula to solve for slope is m=\frac{y_2-y_1}{x_2-x_1}.

m=\frac{3-12}{7-3} =\frac{-9}{4} =-\frac{9}{4}

Now that we have the slope, we can plug in any point.

12=-9/4(4)+b           [multiply]

12=-9+b                   [add both sides by 9]

b=21

Now that we know the y-intercept, the equation is y=-9/4x+21.

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(b)<br> 4x+3<br> 2x-1<br> - 2 =<br> 6x+2<br> 2x-1
irga5000 [103]

Answer:

56

Step-by-step explanation:

3 0
3 years ago
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murzikaleks [220]
Y=44
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3 0
4 years ago
A rectangular vegetable patch has an area of 56 square meters and a
vredina [299]

Answer:

The dimensions of the vegetable patch is 8 m by 7 m.

Step-by-step explanation:

Area of a vegetable patch is 56 square meters and the perimeter is 30 m.

If l is length and b is breadth, then area and perimeter of a rectangle is given by :

A=l\times b

P=2(l+b)

Substituting the values in the above formulas as :

l\times b=56\ ....(1)

and

2(l+b)=30\\\\l+b=15\ .....(2)

We need to solve equation (1) and (2) to find the values of l and b such that :

Equation (2), l = 15 - b

Equation (1) becomes,

(15-b)b=56\\\\b=7\ m, 8\ m

If b = 7 m, so, l = 8 m

If b = 8 m, l = 7 m

So, the dimensions of the vegetable patch is 8 m by 7 m.

4 0
3 years ago
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Zina [86]

Answer:

99

Step-by-step explanation:

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4 0
3 years ago
3/8 ÷7/2 evaluates to
alina1380 [7]

Answer:

3/28

Step-by-step explanation:

You can rewrite 3/8 ÷7/2 to 3/8 x 2/7

then you can simplify which is 3/28

8 0
3 years ago
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