This is what you would do
120 x 17= 2040
Or you could do 12 x 17 then, add a zero to the end of it.
Then you would divid from what you got when you did 120 x 17 by 60
That should give you the answer.
Hope this helps if im not mistaken it should be 34
2040 <span>60 </span>= 34
34 = 340 to the nearest tenth
34 = 34 to the nearest hundredth
34 = 34 to the nearest thousandth
= 0 to the nearest tenth
= 0 to the nearest hundredth
= 0 to the nearest thousandth
Answer:
$9.00
Step-by-step explanation:
4x + 12 = 48 - First, subtract 12 from each side of the equation.
4x = 36 - Then, divide each side by 4 to get x by itself.
x = 9 - After dividing by 4, we are left with x = 9, so 1 ticket costs
$9.00
The last image is the graph of 
In fact, it is an increasing exponential function, and it passes through the points
, which reflects the fact that
and
, which reflects the fact that
.
Now,
is a child of the parent function we just described. Precisely, it is the result of the transformation 
In general, every time you perform a transformation like
, you translate the graph horizontall, k units to the left if k is positive, and k units to the right if k in negative.
Since in this case
, we have a horizontal translation of 4 units to the right.
So, the correct option is the third one, because:
- The first graph is the parent function translated 4 units to the left
- The second graph is the parent function translated 4 units down
- The third graph is the parent function translated 4 units to the right
- The fourth graph is the parent function
Answer:
(7^9)/4 = 40,353,607/4
Step-by-step explanation:
Assuming each digit is used once and exponentiation is allowed, the largest numerator and smallest denominator will result in the largest fraction.
__
If other functions, such as factorial are allowed, then there might need to be a limit on the number of times they are applied. For example,
(7!)^(9!)/4 has about 1 million digits
something like ...
((7!)^(9!))!/4 has many more digits than that
and you can keep piling on the factorial symbols to any desired depth.