One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:
And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees
Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel
Answer:
Give one possible reason why is it important to eat fish
Answer:
4x + x + 7) - 2x+8 - 4 by substituting x= 1 and x = 2. А. 6x + 11 B. 3(x+7) C. 2(3x + 16) D. 3x + 16
Step-by-step explanation:
Answer
That should be it!
Step-by-step explanation:
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Answer:
m∠A = 72°.
m<B = 108°.
Step-by-step explanation:
In a parallelogram, the opposite angles are congruent.
Therefore, we can set the two expressions equal to each other:
5y - 3 = 3y + 27
Add 3 to both sides:
5y = 3y + 30
Subtract 3y from both sides:
2y = 30
Divide both sides by 2:
y = 15
Substitute this value of y into an expression to solve for the measure of ∠A:
5(15) - 3 = 72°. m∠A = 72°.
In parallelograms, the neighboring angles are supplementary. Therefore:
m∠A + m∠B = 180°
72° + m∠B = 180°
m<B = 108°.
